Ask question

Ask question

All categories

4 years ago

12

Calculate the hydrogen-ion concentration [H+] for an aqueous solution in which the hydroxide-ion concentration [OH-] is 1 x 10^-

10 mol/L. Is this solution acidic, basic or neutral? Please show work. *

1 answer:

Gemiola [76]4 years ago

7 0

Answer:

pH = -(log 10^-10)

= -(-10)

=10

so the solution is basic in nature

You might be interested in

If zinc chloride weighs 136.28 g/mol, what is its molecular formula? show calculations

hjlf

We know that Zinc (Zn) has a molar mass of 65.39 g/mol. Hence the remaining is:

136.28 - 65.39=70.89

While molar mass of Chlorine (Cl) is 35.453 g/mol .

70.89 / 35.453 =2 => Cl

<span>So the formula is ZnCl2</span>

3 0

4 years ago

There is enough energy in air at room temperature to change some

Pavel [41]

Answer:

hi

Explanation:

There is enough energy in air at room temperature to change some liquids to gases. The temperature of ice water is lower than the temperature of dry ice in alcohol. Carbon dioxide can change directly from the solid phase to the gaseous phase. ... Absolute zero is the temperature at which there is no molecular motion.

Answer: True

8 0

3 years ago

Consider the hypothetical reaction A(g)←→2B(g). A flask is charged with 0.77 atm of pure A, after which it is allowed to reach e

ankoles [38]

<u>Answer:</u>

<u>For A:</u> The total pressure in the flask at equilibrium is 1.19 atm

<u>For B:</u> The value of $K_p$ for the given equation is 2.016

<u>Explanation:</u>

We are given:

Initial partial pressure of A = 0.77 atm

Equilibrium partial pressure of A = 0.35 atm

<u>For A:</u>

For the given chemical equation:

$A(g)\rightleftharpoons 2B(g)$

<u>Initial:</u> 0.77

<u>At eqllm:</u> 0.77-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.77-x)=0.35\\\\x=0.42$

Equilibrium partial pressure of B = 2x = (2 × 0.42) = 0.84 atm

Total pressure in the flask at equilibrium = $p^A_{eq}+p^b_{eq}=[0.35+0.84]atm=1.19atm$

Hence, the total pressure in the flask at equilibrium is 1.19 atm

<u>For B:</u>

The expression of $K_p$ for given equation follows:

$K_p=\frac{(p_B)^2}{p_A}$

Putting values in above expression, we get:

$K_p=\frac{(0.84)^2}{0.35}\\\\K_p=2.016$

Hence, the value of $K_p$ for the given equation is 2.016

7 0

3 years ago

Ahat [919]

Answer:

$KClO_3$

Explanation:

Hello!

In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

$m_O=22.9g-7.33g-6.65g=8.92g$

Next, we compute the moles of each element:

$n_K=\frac{7.33g}{39.9g/mol}= 0.184mol\\\\n_{Cl}=\frac{6.65g}{35.45g/mol}=0.188mol \\\\n_O=\frac{8.92g}{16.00g/mol} =0.5575mol$

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

$K=\frac{0.184}{0.184}=1.0 \\\\Cl=\frac{0.187}{0.184}=1.0\\\\O=\frac{0.5575}{0.184} =3.0$

Therefore, the empirical formula is:

$KClO_3$

Regards!

3 0

3 years ago

Which gray matter component of the medulla oblongata relays information to the thalamus?.

hodyreva [135]

Gracile nucleus gray matter component.

The thalamus is a paired gray matter structure of the diencephalon located near the center of the brain. It is above the midbrain or mesencephalon, allowing for nerve fiber connections to the cerebral cortex in all directions — each thalamus connects to the other via the interthalamic adhesion. The thalamus forms the upper and lateral walls of the third ventricle while the dorsal surface is part of the floor of the body of the lateral ventricle. Laterally, the thalamus limits with the posterior arm of the internal capsule. Anterolaterally, it limits with the head of the caudate and ventral nucleus with the subthalamus and hypothalamus.

To know more about thalamus click here:

brainly.com/question/13179936

#SPJ4

7 0

1 year ago