Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0
M HCl)
V1 = 0.5 liters
Answer: a. 410 K
b. 296 K
c. 394 K
d. -180 °C
e. 224°C
f. -3 °C
Explanation:
For °C to K : use °C + 273 = K
For K to °C : use °C = K - 273
Answer:
Mass = 917.4 g
Explanation:
Given data:
Number of molecules = 3.00 ×10²⁴ molecules
Mass in gram = ?
Solution:
1 mole contain 6.022 × 10²³ molecules
3.00 ×10²⁴ molecules × 1 mol / 6.022 × 10²³ molecules
0.5×10¹ mol
5 mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 5 mol × 183.48 g/mol
Mass = 917.4 g
Answer:
7?
Explanation:
Its somewhat hard to comprehend the question, but if the way I read it was right, its 7.
Answer:
The concentration of this sodiumhydroxide solutions is 0.50 M
Explanation:
Step 1: Data given
Mass of sodium hydroxide (NaOh) = 8.0 grams
Molar mass of sodium hydroxide = 40.0 g/mol
Volume water = 400 mL = 0.400 L
Step 2: Calculate moles NaOH
Moles NaOH = mass NaOH / molar mass NaOH
Moles NaOH = 8.0 grams / 40.0 g/mol
Moles NaOh = 0.20 moles
Step 3: Calculate concentration of the solution
Concentration solution = moles NaOH / volume water
Concentration solution = 0.20 moles / 0.400 L
Concentration solution = 0.50 M
The concentration of this sodiumhydroxide solutions is 0.50 M
