Question

A rectangle garden has a width that is 8 feet less than twice the length. Find the dimensions if the perimeter is 20 feet

Answer 1

Width = 4ft

Length = 6ft

Explanation:

Let length = l ,

So, width = 2l-8

Perimeter of rectangle = 2x(length + width)

According to the question,

$20ft = 2X(l + 2l-8)\\20ft = 2X(3l -8)\\ 10ft = 3l-8\\18ft = 3l \\ l = 6ft$

Hence,

Width = 4ft

Length = 6ft