If Jan had 10<br> Apples and gave 4 to him, how many apples does Jan have left?

53% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

faltersainse [42]

Answer:

a

$P(X = 5) = 0.2423$

b

$P( X \ge 6 )= 0.4516$

c

$P( X < 4 )= 0.12694$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.53

The sample size is n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly five is mathematically represented as

$P(X = 5) = ^{10}C_5 * 0.53^5 * (1- 0.53)^{10-5}$

=> $P(X = 5) = 252 * 0.04182 * 0.023$

=> $P(X = 5) = 0.2423$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is at least six is mathematically represented as

$P( X \ge 6 )= P( X = 6) + P( X = 7) + P( X = 8) + P( X = 9) + P( X = 10)$

=> $P( X \ge 6 )= [^{10}C_6 * [0.53]^6 * (1- 0.53)^{10-6}] + [^{10}C_7 * [0.53]^7 * (1- 0.53)^{10-7}] + [^{10}C_8 * [0.53]^8 * (1- 0.53)^{10-8}] + [^{10}C_9 * [0.53]^9 * (1- 0.53)^{10-9}] + [^{10}C_{10} * [0.53]^{10} * (1- 0.53)^{10-10}]$

=> $P( X \ge 6 )= [0.227] + [0.1464] + [0.0619] + [0.0155] + [0.00082]$

=> $P( X \ge 6 )= 0.4516$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is less than four is mathematically represented as

$P( X < 4 )= P( X = 3) + P( X = 2) + P( X = 1) + P( X = 0)$

=> $P( X < 4 )= [^{10}C_3 * 0.53^3 * (1- 0.53)^{10-3}] + [^{10}C_2 * 0.53^2 * (1- 0.53)^{10-2}] + [^{10}C_1 * 0.53^1 * (1- 0.53)^{10-1}] + [^{10}C_0 * 0.53^0 * (1- 0.53)^{10-0}]$

=> $P( X < 4 )= 0.09051 + 0.03 + 0.0059 + 0.000526$

=> $P( X < 4 )= 0.12694$

5 0

2 years ago

A tiny but horrible alien is standing at the top of the empire state building (which is 443 meters tall) and threatening to dest

valentina_108 [34]

Answer: $87.7^{\circ}$

Step-by-step explanation:

Height of the building AB= 443 meters

Distance between the building and the agent at the ground BC= 18 meters

Let x be the angle the agent should shoot his laser gun

Since ΔABC is a right triangle, then

$\tan\ x=\frac{AB}{BC}$

$\Rightarrow\tan\ x=\frac{443}{18}\\\Rightarrow\tan\ x=24.6111\\\Rightarrow\ x=\tan^{-1}(24.61)\\\Rightarrow\ x=87.67^{\circ}\approx87.7^{\circ}$

7 0

3 years ago

Read 2 more answers

Help find slope of each line

gizmo_the_mogwai [7]

Slope=-5

as the line goes 5 down and 1 right

3 0

2 years ago

Read 2 more answers

Solve question 10 using substitution or elimination. Show all work.

BlackZzzverrR [31]

Solid paper costs 1.75 each
Printed paper costs 2.50 each

Given:
Ben = $43.50 (12 rolls solid paper and 9 rolls of
printed paper)
Joel = $51.50 (8 rolls solid paper and 15 rolls of
printed paper)
Let x = solid paper
Let y= printed paper
12x + 9y = 43.50
8x + 15y = 51.50

Find X:
8x + 15y = 51.50
8x = 51.50 - 15y
x= (51.50 - 15y)8

Substitute X:
12x + 9y = 43.50
12(51.50 - 15y)/8 + 9y = 43.50
(618 - 180y)/8 + 9y = 43.50
8 (618 - 180y)/8 + 8*9y = 43.50 * 8
618-180y + 72y =348
-108y = 348 - 618
-108y =-270
-108y/-108=-270/-108

Y= 2.50

x = (51.50 - 15y)/8
x = (51.50 - 15(2.5) /8
x= (51.50 - 37.50\8
X = 14/8

X = 1.75

To check: x = 1.75; y = 2.5
12x + 9y = 43.50
12(1.75) + 9(2.5) = 43.50
21 + 22.50 = 43.50
43.50 = 43.50
8x + 15y = 51.50
8(1.75) + 15(2.5) = 51.50
14 + 37.50 = 51.50
51.50 = 51.50

Hope that helps! Have a good day :)

5 0

1 year ago

Explain how to model the problem with algebra tiles and

gregori [183]

Answer:someone answer the question already

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If Jan had 10 Apples and gave 4 to him, how many apples does Jan have left?