The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Meg would be a to be correct
Answer:
12
Step-by-step explanation:
Answer:
x=-5
Step-by-step explanation:
10x + 15 = 5x-10
-5x -5x
5x+15 = -10
-15 -15
5x = -25
/5 /5
x = -5
Length x width = formula of finding the area of a rectangle
2 3/7 x 2 4/5 = 6 4/5 (6.8)
The area of the rectangle is 6 4/5 / 6.8
