Answer:
Raining Company and Tanning Company
An Uncollectible Expense of $17,500 will be credited to the Allowance for Doubtful Accounts to bring the credit balance to $20,000.
Step-by-step explanation:
Since the accounts receivable balance is $200,000, there is nothing to do with the credit sales of $1,300,000.
The Allowance for Doubtful Accounts after adjustment should have a credit balance of $20,000 ($200,000 x 10%).
With a credit balance of $2,500 before adjustment, it will be adjusted (credited) with Uncollectible Expense of $17,500. This brings the adjusted balance to $20,000 which represents 10% of the accounts receivable balance of $200,000.
Note that the Allowance for Doubtful Accounts is a contra (credit) account to the Accounts Receivable account. This allowance is a way to prudently provide for credit risk as required by Generally Accepted Accounting Principles.
Answer:
B.
![{ \tt{f(x) = \sqrt[3]{x + 11} }}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7Bf%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7Bx%20%2B%2011%7D%20%7D%7D)
let the inverse of f(x) be m:
![{ \tt{m = \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3} = x + 11}} \\ { \tt{ {m}^{3} - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) = {m}^{3} - 11 }}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7Bm%20%3D%20%20%5Csqrt%5B3%5D%7Bx%20%2B%2011%7D%20%7D%7D%20%5C%5C%20%7B%20%5Ctt%7B%20%7Bm%7D%5E%7B3%7D%20%20%3D%20x%20%2B%2011%7D%7D%20%5C%5C%20%7B%20%5Ctt%7B%20%7Bm%7D%5E%7B3%7D%20%20-%2011%20%3D%20x%7D%7D%20%5C%5C%20%7B%20%5Ctt%7B%20%7Bf%7D%5E%7B%20-%201%7D%28x%29%20%3D%20%20%7Bm%7D%5E%7B3%7D%20%20-%2011%20%7D%7D)
substitute for x in place of m:

Answer: Choice B) -infinity < x < infinity
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Explanation:
The parabola goes on forever to the left and to the right. We can plug in any x value without worrying about something as a division by zero error. So any real number will work.
Writing -infinity < x < infinity refers to the entire number line, which is the set of all real numbers.
This is the associative property of addition because the grouping of addends does not change the some no matter where you place the numbers in the parenthesis.
So there are 2 dogs to every 3 cats (put into words)
in order to reach 15 total multiply both 2 and 3 by 3
2x3 = 6
3x3 = 9
so there are 6 dogs and 9 cats