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4 years ago

At what position on the number line is the red dot located?

Mathematics

1 answer:

anygoal [31]4 years ago

7 0

Answer:

Step-by-step explanation:

The sq rt of 38 would be about 6.16 which is close to where the red dot is located, so the answer would be the sq rt of 38.

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Which equation can be used to represent six added to twice the sum of a numbee and four is equal to one half of the difference o

Ronch [10]

Answer: $6 + 2 (x+4)$ = $\frac{3}{2}$ $(3-x)$

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

$6 + 2 (x+4)$

one half of the difference of three and the number means :

$\frac{3}{2}$ $(3-x)$

combining the two , we have

$6 + 2 (x+4)$ = $\frac{3}{2}$ $(3-x)$

6 0

4 years ago

Solve the system of equations using elimination<br> x-y=3<br> 2x+2y=50

pishuonlain [190]

Answer:

X=14

Y=11

Step-by-step explanation:

14-11=3

14x2=28

11x2=22

22+28=50

Hope that works :)

6 0

3 years ago

Read 2 more answers

Jeff adds 5 Xbox games to his collection but then has to give half of his collection away. He now has 8 Xbox games. How many Xbo

ratelena [41]

Answer:

13 i think

Step-by-step explanation:

7 0

3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

4 years ago

Pls help solve!!!!!!!!

Svetradugi [14.3K]

Its also 40°30' because the median is also a bisector in isosceles triangle

5 0

3 years ago