Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
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1) 5000*90/100=4500
2)5000*0.05=250
3)0.05/(90/100)=5.6%
Answer:
Answer Choice A.
Step-by-step explanation:
To find 4C, multiply each and every one of the 6 numerals inside the determinant bars by 4:
48 0 6
4C = 4 -24 28
This is Answer Choice A.
Answer:
27
12
3
0
3
12
27
Step-by-step explanation:
y=3x^2
JUST PLUG IN X
The month in which Company B's payment will first exceed Company A's payment is C) Month 7.
Step-by-step explanation:
Step 1:
Company A offers $6,000 for the first month and increases the salary each month by $5,000.
Company B offers $700 for the first month but doubles the payments each month.
We need to determine which month company B's payment is greater than company A's payment.
Step 2:
According to the table, at month 6 company A pays $31,000 while company B pays $22,400.
However after this month, in the seventh-month company A pays $36,000 while company B pays $44,800, which is higher than company A's salary.
So The month in which Company B's payment will first exceed Company A's payment is C) Month 7.
