Solve the system by the addition method 4x=3y-8 -16x+4y=32

1 answer:

6 0

4x = 3y - 8
4    4
x = ³/₄y - 2

      -16x + 4y = 32
   -16(³/₄y - 2) + 4y = 32
-16(³/₄y) + 16(2) + 4y = 32
      -12y + 32 + 4y = 32
      -12y + 4y + 32 = 32
      -8y + 32 = 32
   - 32 - 32
      -8y = 0
   -8 -8
   y = 0
x = ³/₄y - 2
x = ³/₄(0) - 2
x = 0 - 2
x = -2

(x, y) = (-2, 0)

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#82 will give brainliest to best answer!

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Answer:

$\frac{6}{k-6}$

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ ÷ $\frac{(k-6)^2}{k(k-6)}$ × $\frac{6(k-10)}{k(k + 6)}$ . We know that division is simply multiplication by the reciprocal, so that whole equation will turn into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ × $\frac{k(k-6)}{(k-6)^2}$ × $\frac{6(k-10)}{k(k+6)}$ . Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into $\frac{6}{k-6}$ which is our final answer, as it cannot be simplified further.