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Margaret [11]
3 years ago
6

From 7 boys and 4 girls, how many different committees can be selected consisting of 3 boys and 2 girls?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0
There can be 1 or 2 but a total committee in total with boys and girls would be 4
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Jack, Davis, Faiza, and Marry want to take a picture together. In how many ways can they are arranged?
mafiozo [28]

Answer:

16

Step-by-step explanation:

3 0
2 years ago
2a+3b=5<br> b=a-5 help please
diamong [38]

Answer:

2a + 3b = 5

b = a - 5

Step-by-step explanation:

2a + 3b = 5

b = a - 5

You can write this another way:

2a + 3(a-5) = 5 ( I added the second formula in the first one )

Now you gotta factor out:

2a + 3a - 15 = 5

Here im gonna do plus 15

2a + 3a = 20 ==> 5a = 20

Now if you divide by 5, you get: a = 4

Now you can fill in the second formula again

b = a - 5 (ill fill this in now)

b = 4 - 5 = -1

So, this makes:

a = 4 , b = -1

6 0
3 years ago
Read 2 more answers
Resolber la siguientes problemas
german
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3 0
2 years ago
Please see the photo. It's not 4 or 6.
Verdich [7]

Answer:

x = 9

Step-by-step explanation:

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

5(x - 6 + 5) = 4(x - 3 + 4)

5(x - 1) = 4(x + 1) ← distribute parenthesis on both sides

5x - 5 = 4x + 4 ( subtract 4x from both sides )

x - 5 = 4 ( add 5 to both sides )

x = 9

4 0
2 years ago
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shutvik [7]

Answer:

a<-3

bc -3(-2)=6

so if u go lower which the next number would be -4(-2)=8 which is greaterthan 6

Step-by-step explanation:

5 0
3 years ago
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