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Mila [183]
3 years ago
14

What is the value of c in the equation? 15.3= C/2.1

Mathematics
2 answers:
geniusboy [140]3 years ago
5 0

Answer:

c=32.13

Step-by-step explanation:

yarga [219]3 years ago
4 0

Answer:

c=32.13

Step-by-step explanation:

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The answer is 7, hope this helps!! just plug in 2 for the x and type the answer in :)
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2 years ago
Betty sold 21 out of the 70 quilts she made. What percent of her quilts did Betty sell?
Nina [5.8K]

Answer:

The answer is <em>C</em> or 30%

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3 0
3 years ago
Yolanda makes $11.25 per hour at her part-time job. During one week, she worked 12 2/5 hours and also earned some tips. Her fina
Delicious77 [7]

Answer:

She earned $20 in tips.

Step-by-step explanation:

First, you need to work out how much pay she'd get for 12 hours work:

12 x $11.25 = $135 for 12 hours work

Then, find out 2/5 of $11.25 to find out how much she would get for the 2/5 of an hour she worked:

2/5 of $11.25 = $4.50

Add both these sums together to get her total pay for hours worked:

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Subtract that sum from her total pay to find out how much money she earned in tips:

$159.50 - $139.50 = <u>$20</u>

7 0
3 years ago
Read 2 more answers
PLEASE HELP!! i'm writing a test and i have no idea how to do this. (I'm giving 30 points)
Vesna [10]

Answer:

12/y

Step-by-step explanation:

if you see in the picture the first three numbers 3,6 and 9 you add 3 in each number like 3+3=6 then 6=3 = 9 and 9 + 3 = 12 and so on. ( 45 also comes in this pattern )

have a wonderful day

8 0
2 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

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\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

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\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
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