Answer:
While the coordinates would be a solution to the first equation, they are not for the second equation, so the answer to your question is no.
Step-by-step explanation:
All you have to do is substitute the coordinates into the x and y values.
(2)-2(-1) = 2+2 = 4 We can tell that the coordinates worked for the first equation. Lets see if it works for the second, as well.
3(2) + (-1) = 6-1 = 5 Unfortunately, the coordinates were incorrect for the second equation.
B issssssssssss obvvvvvvvvvvv looll
If 1/3x + 3 = x, then x-1/3 = 3
so
2/3 x = 3
x = 3 * 3/2 = 9/2
Hello
y²+y-6=0
==> y²-2y+3y-6=0
==>y(y-2)+3(y-2)=0
==>y-2)(y+3)=0
==>y=-3 or y=2
Answer C (-3,2)
Answer:
"2" is the exponent
Step-by-step explanation:
There is no exponent in your expression.
__
When the expression is typeset, the superscript text is considered to be an exponent:
When the expression is written in plain text, the exponent is indicated by a caret (^):
