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labwork [276]
3 years ago
7

the temperature at noon is -4F. the temperature at 6:00pm is -12. what is difference between noon and 6:00pm temperature

Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer:

8 degrees Fahrenheit

Step-by-step explanation:

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garri49 [273]

Answer:

The last pair are vertical.

Step-by-step explanation:

7 0
3 years ago
A shopkeeper bird and electric item for rupees 1520 and sold it at 10% loss find the loss amount​
Alex17521 [72]

Answer:

The answer is 152

Step-by-step explanation:

When you have a number in between 9999 and 1000 you can divide by 10 to get ten percent of the number

3 0
3 years ago
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7.   Simplify ((–3)^2)^3.      A. (3)^5 B. (–3)^6 C. (3)^6 D. (–3)^5
alisha [4.7K]
((-3)^2)^3

The rule for raising and exponent to another exponent is:

(a^b)^c=a^(b*c) so:

((-3)^2)^3

(-3)^(2*3)

(-3)^6
6 0
3 years ago
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Someone please solve all equations
Tamiku [17]

17. (a) The formula with CP subject is CP=\frac{SP}{1.1}

(b) The Cost Price of item without GST is $59.50

(c) The GST of item is $5.95

Step-by-step explanation:

Given formula is;

SP = 1.1 * CP

SP = Selling price

CP = Cost price

(a) Rearrange the formula to make CP the subject;

SP = 1.1 * CP

Dividing both sides by 1.1

\frac{SP}{1.1}=\frac{1.1*CP}{1.1}\\\\\frac{SP}{1.1}=CP\\\\CP=\frac{SP}{1.1}

The formula with CP subject is CP=\frac{SP}{1.1}

(b) Use your formula from (a) to find the Cost Price of an item without GST if the selling price is $65.45

SP = $65.45

CP=\frac{65.45}{1.1}\\\\CP=\$59.50

The Cost Price of item without GST is $59.50

(c) Calculate the amount of GST on an item whose selling price is $65.45.

GST = 10% of CP

GST = \frac{10}{100}*CP

GST = 0.1CP

From part (b)

CP = $59.50

GST = 0.1 * 59.50

GST = $5.95

The GST of item is $5.95

Keywords: percentage, multiplication

Learn more about multiplication at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

3 0
3 years ago
The local supermarket buys lettuce each day to ensure really fresh produce. Each morning any lettuce that is left from the previ
jekas [21]

Given Information:

Cost price = $4

Selling price = $10

Salvage value = $1.50

Average demand = μ = 250 boxes

Standard deviation = σ = 34 boxes

Required Information:

Number of lettuce boxes = ?

Answer:

The supermarket should purchase 268 boxes  of lettuce

Step-by-step explanation:

The required number of lettuce boxes that supermarket should purchase is given by

Number of lettuce boxes = μ + (z*σ)

Where μ is the average demand of lettuce boxes, σ is the standard deviation, and z is the z-score which is given by

p = C_us/(C_us + C_os)

The z-score corresponding to probability p will be obtained.

The cost of under stocking is given by

C_us = Selling price - Cost price

C_us = $10 - $4

C_us = $6

The cost of over stocking is given by

C_os = Cost price - Salvage value

C_os = $4 - $1.50

C_os = $2.50

p = C_us/(C_us + C_os)

p = 6/(6 + 2.50)

p = 0.7058

p  = 70.58%

The z-score corresponding to 70.58% probability is approximately 0.54

Number of lettuce boxes = μ + (z*σ)

Number of lettuce boxes = 250 + (0.54*34)

Number of lettuce boxes = 250 + (18.36)

Number of lettuce boxes = 268.36

Number of lettuce boxes ≈ 268

Therefore, the supermarket should purchase 268 boxes of lettuce.

How to use z-table?

Step 1:

In the z-table, find the probability you are looking for and note down the two-digit number of the given row. (e.g 0.5, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table and note down the value in the column for the remaining decimal point in the range of 0.00 to 0.09.

Step 3:

Finally, add the numbers obtained from step 1 and step 2.

8 0
3 years ago
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