the temperature at noon is -4F. the temperature at 6:00pm is -12. what is difference between noon and 6:00pm temperature
1 answer:
You might be interested in
To find the equation, for the x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16) we have to find the nature of the curve.
The correct option is f(x) = –2(x – 2)(x – 4).
Given:
The x-intercepts at (2, 0) and (4, 0).
The y-intercept of (0, –16).
The nature of the graph is quadratic curve. Write the general equation for x-intercept.
Where is number
Substitute 0 for .
We have y-intercept of (0, –16).
The equation would be,
Thus, the correct option is f(x) = –2(x – 2)(x – 4).
Learn more about equitation here:
Answer:
Step-by-step explanation:
Since both are perfect squares use the difference of squares formula with a =
and b = 3
=