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Inessa05 [86]
3 years ago
10

A box contains 10 items, of which 3 are defective and 7are non defective. Two items are randomly selected, one at a time, with r

eplacement, and x is the number of defectives in the sample of two. Explain why x is a binomial random variable
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
Necessary and sufficient conditions for application of binomial distribution :
1. trial must be Bernoulli, i.e. exactly two outcomes (defective or not defective)
2. number of trails is known and not dependent on outcomes (2).
3. probability of each trial must be known and is constant throughout trials (3/10, with replacement)
4. all trials are random and independent of each other.

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Mars2501 [29]

Answer:

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Step-by-step explanation:

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3 0
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Dmitry_Shevchenko [17]

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3 years ago
How to do it? i dont really under stand
dybincka [34]

First, we want to ask "What number divided by 7 <em>is </em>800?" That'll give us a jumping off point to answer the rest of the question.

If dividing some number by 7 gets us 800, that means that <em>multiplying </em>800 by 7 should get us back that number. We find that 800 x 7 = 5600. The first number higher than 5600 is 5601, which, when divided by 7, gets us about 800.14, a number greater than 800. So the lowest whole number that makes the inequality ? ÷ 7 > 800 work is 5601.

7 0
3 years ago
Simplify 15a^2 * 4c * 5ab
gulaghasi [49]

Answer: 300a^3cb

Step-by-step explanation:

$$Simplify the following:$$15 \times 4 \times 5 a^{2} c a b$$$$\begin{aligned}&15 a^{2} \times 4 c \times 5 a b=15 a^{2+1} \times 4 c \times 5 b: \\ \\&15 \times 4 \times 5 a^{2+1} c b\end{aligned}$$$$\begin{aligned}&2+1=3 \\ \\&15 \times 4 \times 5 a^{3} c b \end{aligned}$$$$\begin{aligned}&15 \times 4=60 \\ \\&60 \times 5 a^{3} c b\end{aligned}$$$$60 \times 5=300$$Answer:$$300 a^{3} c b$$

6 0
2 years ago
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