All categories

4 years ago

Find the mean median and mode of 15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13

2 answers:

7 0

Mean: add them all and divide by the count of numbers: 9.27
Median: middle value when sorted ascending: 10
Mode: number that occurs most often: 13

That's the first set of numbers. Now you know how to do the second! Excel can help you with this fast!

forsale [732]4 years ago

4 0

1. Median= 9
Mode= 13

2. Mean= 75.772727272727
Median= 76.5
Mode= 63

You might be interested in

6x^2 +7x^3 +8x^5 +9 What it the degree of the polynomial

DaniilM [7]

The degree of the polynomial is 5.

7 0

4 years ago

Read 2 more answers

Kalsom answers 25 questions in math tests. He scored 81% to 93%. Calculate all possible number of questions successfully answere

cricket20 [7]

Answer:

21 and 22

Step-by-step explanation:

Let's work backward from that 81%: x/25 = 0.81 yields x = 20.25. Nominally, 20.25 / 25 = 0.81, but x must be an integer. Let's round 20.25 off to 20.

Thus, if Kalsom got 81%, it was a result of his having done 20 questions correctly.

81% corresponds to 20 questions correct;

82% to 20.5 questions correct, or, rounding up, to 21 questions correct;

83% to 20.75, or 21;

84% to 21 questions correct; this is the only result that makes sense (whole number of questions answered correctly)

85% to 21.25;

86% to 21.5;

87% to 21.75;

88% to 22 questions correct (this makes sense, unlike the last three)

89% to 22.25;

90% to 22.5;

91% to 22.75;

Assuming that the number of questions correct MUST be integer, then the possible number correct are 21 and 22, corresponding to 84% and 88% respectively.

4 0

4 years ago

HELP with these questions

zlopas [31]

Step-by-step explanation:

transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

0 = ln (x - 4)

$e^{0} = e^{ln (x - 4)}$

1 = x - 4

+4 +4

5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

1 = ln (x - 4)

$e^{1} = e^{ln (x - 4)}$

e = x - 4

+4 +4

e + 4 = x

6.72 = x

(6.72, 1)

Domain: x - 4 > 0

+4 +4

x > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

= - 3⁰⁺⁵

= - 3⁵

= -243

Horizontal Asymptote: y = 0 (explanation above)

5 0

4 years ago

Math III WSD CRC QT 1.25 CR

Semenov [28]

Answer:

5ff5yvy hh h

Step-by-step explanation:

ctvtvh j h h h j

8 0

3 years ago

I would love if someone would help me

mart [117]

I’m hoping this helps (but hopefully now you can give the brainliest to the person above)
I’m not very familiar with the square roots method but I believe you try and isolate the term that is squared.

4 0

3 years ago