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Delvig [45]
3 years ago
12

I need help please on all

Mathematics
1 answer:
natka813 [3]3 years ago
6 0
1. B. The retail price would be the purchase price plus the markup.
So p+.40p = 1.40 p = 1.4 p. (p is really 1 p)
C. You would multiply: 1.4(56) = $78,40
D. You could multiply .4p = .4(56). OR subtract: 78.40-56 = $22.40

2. Done
3. 10(.35) = $3.50 —— 10+3.50=$13.50
4. 40(.25) = $10 ———- 40+10=$50
5 Done
6. $30.50/30% markdown 30.50(.30) = $9.15; 30.50-9.15= $21.35
7. $105/75% markdown 105(.75) = 78.75; 105-78.75= $26.25
8. $325/15% markdown 325(.15) = 48.75; 325-48.75= $276.25
9. C/40%markup Total retail:.40c + c = 1.40C
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A is 32 because

2a=64
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How do you find what the IQR
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Bow hello IQR is 21 + 1 -1 = 21
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Which graph matches the equation y+3=2(x+3)?
Vlad1618 [11]

Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

y+3=2(0+3)

y+3 = 6

y = 6 - 3

y = 3

Then, point (0, 3) is on the line.

8 0
3 years ago
The University of Texas at Austin has three times as many students enrolledas the University of Miami. The University of Califor
harina [27]

Answer:

University of Texas has 46,500 students, University of California has 34,000 students and University of Miami has 15,500 students.

Step-by-step explanation:

Represent Texas with T, Miami with M and California with C. With the given information, the following equations were obtained.

T = 3 × M

T – 3M = 0 ………………………….(i)

C = 3,000 + 2 × M

C – 2M = 3,000…………………..(ii)

T + C + M = 96,000…………….(iii)

By rearranging, we have:

1T + 0C – 3M = 0 ………………………….(i)

0T + 1C – 2M = 3,000…………………..(ii)

1T + 1C + 1M = 96,000………….…….(iii)

The Augmented Matrix is:

\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

Making \left[\begin{array}{ccc}T\\C\\M\end{array}\right] the subject of the formula we have:

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \frac{\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]}{\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]}

Let’s say matrix A = \left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right], the inverse of matrix A = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] is determined by the formula \frac{Adjoint(A)}{determinant(A)}. This can also be computed directly on a scientific calculator.

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

= \left[\begin{array}{ccc}46,500\\34,000\\15,500\end{array}\right]

T = 46,500

C = 34,000

M = 15,500

6 0
4 years ago
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A basketball player shoots free throws and makes them with probability 1/7. What is the probability of the event the player will
Liula [17]

Answer:

216/343 or 0.6297 (4dp)

Step-by-step explanation:

Anytime the probability of an event occurs more than once in a particular order (one time after another in the same instance), then the probability is multiplied together. If the probability of him making the shot is 1/7, then the probability of him missing it is 6/7. This is because this is the only other possible outcomes and all outcome probabilities must add to 1 (1-1/7 - 6/7).

So, if he misses it three times in a row then the probability is:

6/7 (probability miss this first time) x 6/7 (probability miss second time) x 6/7 (probability miss 3rd time).

6/7 x 6/7 x 6/7 = 216/343

or 0.6297 (4dp)

Hope this helped!

5 0
4 years ago
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