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2 years ago

I need help please on all

Mathematics

1 answer:

natka813 [3]2 years ago

6 0

1. B. The retail price would be the purchase price plus the markup.
So p+.40p = 1.40 p = 1.4 p. (p is really 1 p)
C. You would multiply: 1.4(56) = $78,40
D. You could multiply .4p = .4(56). OR subtract: 78.40-56 = $22.40

2. Done
3. 10(.35) = $3.50 —— 10+3.50=$13.50
4. 40(.25) = $10 ———- 40+10=$50
5 Done
6. $30.50/30% markdown 30.50(.30) = $9.15; 30.50-9.15= $21.35
7. $105/75% markdown 105(.75) = 78.75; 105-78.75= $26.25
8. $325/15% markdown 325(.15) = 48.75; 325-48.75= $276.25
9. C/40%markup Total retail:.40c + c = 1.40C

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Maria took out an unsubsidized Stafford loan of $6,925 to pay for college. She plans to graduate in 4 years. The loan had a dura

Finger [1]

Answer:

$144.70

Step-by-step explanation:

Calculation to determine how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization

First step is to determine the Interest only monthly repayments

Using this formula

I=Prt

where,

P=$6925

r=0.05/1

t=1

Let plug in the formula

I=6925*0.05/12

I= $28.854166666

Second step is to determine the amount she will owe after 4 years

Using this formula

S=P(1+r)n

Let plug in the formula

S=6925*(1+0.05/12)4*12

S=6925*(1+0.05/12)48

S=$8454.70

Third step is to determine the Interest part

Interest =8454.70 - 6925

Interest = $1529.70

Now let determine the how much greater will the amount of interest capitalized be

Interest capitalized=1529.70 - 1385.00

Interest capitalized =$144.70

Therefore how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization is $144.70

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2 years ago

A diver went 25.65 feet below the surface of the ocean, and then 16.5 feet further down, he rose 12.45 feet.

Rasek [7]

If you are trying to find where he is the answer is -29.7

Hope this helps!

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2 years ago

Read 2 more answers

The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less tha

kirill115 [55]

Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57

5 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

2 years ago

It is difficult to manage data. For example, it is common for customers to move and for companies to go out of business. This is

Fantom [35]

Answer:

a) Data degradation

Step-by-step explanation:

These are the options for the question.

a) Data degradation

b) Data rot

c) Data security

d) Scattered data

From the question, we are informed about how difficult it's to manage data. For example, it is common for customers to move and for companies to go out of business. This case is an example of Data degradation. Data degradation can be regarded as

corruption of computer data, or gradual alterations of data, and this could be as a result of accumulation of failures in storage devices that store the data, this failure can be critical one or non-critical one

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2 years ago