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3 years ago

I need help please on all

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

1. B. The retail price would be the purchase price plus the markup.
So p+.40p = 1.40 p = 1.4 p. (p is really 1 p)
C. You would multiply: 1.4(56) = $78,40
D. You could multiply .4p = .4(56). OR subtract: 78.40-56 = $22.40

2. Done
3. 10(.35) = $3.50 —— 10+3.50=$13.50
4. 40(.25) = $10 ———- 40+10=$50
5 Done
6. $30.50/30% markdown 30.50(.30) = $9.15; 30.50-9.15= $21.35
7. $105/75% markdown 105(.75) = 78.75; 105-78.75= $26.25
8. $325/15% markdown 325(.15) = 48.75; 325-48.75= $276.25
9. C/40%markup Total retail:.40c + c = 1.40C

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X/7- y/5=1 solve for y

Usimov [2.4K]

Answer:

y = 5/7 x -5

Step-by-step explanation:

X/7- y/5=1

Multiply each side by 35 to clear the fractions

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5x - 7y = 35

Subtract 5x from each side

5x-5x-7y = -5x+35

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Divide each side by -7

-7y/-7 = -5x/-7 +35/-7

y = 5/7 x -5

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The answer would be 60

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Juanita runs every third day and swims every fifth day. If Juanita runs and swims today, in how many days will she run and swim

Ber [7]

we know that

The least
common multiple (LCM) of two or more numbers is the least

number, other than zero, that is a multiple of all the numbers.

In this problem, we are looking for the least common multiple of $3$ and $5$

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On the $15th$ day after today, she will do both on the same day

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3 years ago

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50 POINTS

Tcecarenko [31]

Answer:

Part 1: C. $3,159.30

Part 2. C. –5; –135; –10,935

Step-by-step explanation:

Part 1:

Price of the boat = $ 16,600

Depreciation rate = 14% = 0.14

Time of utilization of the boat = 11 years

Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat

Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹

Price of the boat after 11 years = 16,600 * 0.1903

Price of the boat after 11 years = $ 3,159.30

Part 2:

Let's find out the first term of the sequence given:

A(1) = -5 * 3¹⁻¹

A(1) = -5 * 1

A(1) = -5

Let's find out the fourth term of the sequence given:

A(4) = -5 * 3⁴⁻¹

A(4) = -5 * 3³

A(4) = -5 * 27

A(4) = -135

Let's find out the eighth term of the sequence given:

A(8) = -5 * 3⁸⁻¹

A(8) = -5 * 3⁷

A(8) = -5 * 2,187

A(8) = -10,935

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3 years ago

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.

Firdavs [7]

Answer:

New can holds $112.25\,\,cm^3$ more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is $339.12\,\,cm^3$

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = $339.12\,\,cm^3$

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = $\frac{6}{2}=3\,\,cm$

h = 12 cm

R = $3(1.1)=3.3.\,\,cm$

H = $12(1.1)=13.2\,\,cm$

New volume (V) = $\pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3$

So,

$V-v=451.37-339.12=112.25\,\,cm^3$

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4 years ago