All categories

2 years ago

I need help please on all

Mathematics

1 answer:

natka813 [3]2 years ago

6 0

1. B. The retail price would be the purchase price plus the markup.
So p+.40p = 1.40 p = 1.4 p. (p is really 1 p)
C. You would multiply: 1.4(56) = $78,40
D. You could multiply .4p = .4(56). OR subtract: 78.40-56 = $22.40

2. Done
3. 10(.35) = $3.50 —— 10+3.50=$13.50
4. 40(.25) = $10 ———- 40+10=$50
5 Done
6. $30.50/30% markdown 30.50(.30) = $9.15; 30.50-9.15= $21.35
7. $105/75% markdown 105(.75) = 78.75; 105-78.75= $26.25
8. $325/15% markdown 325(.15) = 48.75; 325-48.75= $276.25
9. C/40%markup Total retail:.40c + c = 1.40C

You might be interested in

If the length of diagonal of a square is 4√2 cm, find it's length, perimeter and area.

Sonbull [250]

Answer:

As Per Provided Information

Length of diagonal of square is 4√2 cm

We have been asked to find the length , perimeter and area of square .

First let's calculate the side of square .

Using Formulae

$\boxed{\bf \:Diagonal_{(Square)} \: = side \sqrt{2}}$

On substituting the value in above formula we obtain

$\qquad\longrightarrow\sf \:4 \sqrt{2} = side \sqrt{2} \\ \\ \\ \qquad\longrightarrow\sf \:4 \cancel{\sqrt{2}} = side \cancel{ \sqrt{2}} \\ \\ \\ \qquad\longrightarrow\sf \:side \: = 4 \: cm$

Therefore,

Length of its side is 4 cm.

Finding the perimeter of square.

$\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}$

Substituting the value we obtain

$\qquad\longrightarrow\sf \:Perimeter_{(Square)} \: = 4 \times 4 \\ \\ \\ \qquad\longrightarrow\sf \:Perimeter_{(Square)} = 16 \: cm$

Therefore,

Perimeter of square is 16 cm .

Finding the area of square .

$\boxed{\bf \: Area_{(Square)} = {side}^{2}}$

Substituting the value we get

$\qquad\longrightarrow\sf \:Area_{(Square)} \: = {4}^{2} \\ \\ \\ \qquad\longrightarrow\sf \:Area_{(Square)} = 16 \: {cm}^{2}$

Therefore,

Area of square is 16 cm².

3 0

2 years ago

How do i solve this quesiton 6(x − 2) > 15

trasher [3.6K]

Answer:

Step-by-step explanation:

$\displaystyle\ \!\!6(x-2)>15 \\\\6x-12>15 \\\\6x>27\\\\ \boldsymbol{x>4,5 \ \ or \ \ x\in(4,5\ ; \infty)}$

7 0

2 years ago

4•6*2 to the third power

Eddi Din [679]

Answer:

778.688

.........................

7 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago

If 25=4x-7, then x =

sasho [114]

Answer:

x=8

Step-by-step explanation:

Move all terms that don't contain x to the right side and solve.

6 0

3 years ago