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2 years ago

HELP PLEASEEE ILL MARK BRAINLIEST questions are in the pic

Mathematics

2 answers:

julsineya [31]2 years ago

3 0

Answer:

Please ask you instructor for a more elaborated question.

Step-by-step explanation:

Fiesta28 [93]2 years ago

3 0

Answer:

1/2-up 1 and to the side 2

1/4- up 1 and to the side four

no because 1/2 is not 1/4.

Step-by-step explanation:

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Which function is linear?

natali 33 [55]

Answer:

B) f(x)=13x+4 and C) f(x)=|3x| − 4

5 0

2 years ago

Only 30 minutes please help

andrezito [222]

Answer:

B, and i don't for the second one

Step-by-step explanation:

4 0

3 years ago

Q: In an examination 14% of the students failed and 559 students passed. Find

topjm [15]

100% - 14% = 86%
86% of what gives you 559
559 * 100 = 55,900/86 = 650
650 students in total
650 - 559 = 91
Solution: 91 students failed

7 0

2 years ago

NEED HELP ASAP

Katyanochek1 [597]

Find the annual earnings if a worker is paid $743.75 semimonthly.

Answer: A worker is paid $743.75 semimonthly.

Semimonthly is twice a month.

Therefore, a worker is paid $ $743.75 \times 2 =1487.5$ monthly

There are 12 months in a year.

Therefore a worker is paid $ $1487.5 \times 12 =17850$ annually

Hence, the option b. $17,850.00 is correct

8 0

2 years ago

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

3 0

2 years ago