Answer:
6.75×10^13N
Explanation:
The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.
Mathematically, F = kq1q2/r² where;
q1 and q2 are the charges
r is the distance between the charges
F is the force of attraction
k is the coulombs constant
Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9×10^9Nm²/C²
Substituting the given values in the formula we have;
F =9×10^9×5×15/0.1²
F = 6.75×10^11/0.01
F = 6.75×10^13N
Therefore the electric force between them is 6.75×10^13N
