4x=20-8y
x=5-2y now use this value of x in the second equation...
3(5-2y)+6y=15
15-6y+6y=15
15=15 This is true for any y or x value.
So there are infinitely many solutions as the two equations describe the same line.
Answer:
length and width=4
height=8
Step-by-step explanation:
Hello to solve this problem we must propose a system of equations of 3x3, that is to say 3 variables and 3 equations.
Ecuation 1
Leght=Width
.L=W
Ecuation 2
To raise the second equation we consider that the length and width of 4 inches less than the height of the box
H-4=W
Ecuation 3
To establish equation number 3, we find the volume of a prism that is the result of multiplying length, width, and height
LxWxH=128
From ecuation 1(w=h)

solving for H

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<em>Using ecuation 2</em>
H-4=W

Now we find the roots of the equation, 2 of them are imaginary, and only one results in 4
W=4in
L=4in
to find the height we use the ecuation 2
H-4=W
H=4+W
H=4+4=8
H=8IN
Answer:
I have wrote just answers
Answer:
-5 =x
Step-by-step explanation:
3^(x-1) = 9^(x+2)
Replace 9 with 3^2
3^(x-1) = 3^2^(x+2)
We know that a power to a power means the powers are multiplied
a^b^c = a^(b*c)
3^(x-1) = 3^(2x+2)
When the bases are the same, the powers have to be the same
x-1 = 2x+4
Subtract x from each side
x-x-1 =2x-x+4
-1 =x+4
Subtract 4 from each side
-1-4 =x+4-4
-1-4 = x
-5 =x