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Brilliant_brown [7]
3 years ago
5

East High School scored a total of 71 points in their final basketball game of the season. The team successfully made a total of

32 baskets. The score was composed of two-point baskets and three-point baskets. The following system of equations can be used to model the number of two-point baskets, x, and the number of three-point baskets, y, that were made during the game. First, determine the point on the graph that represents the solution to the system of equations. Notice that one of the equations in the system has already been graphed. Then, determine the number of two-point baskets and three-point baskets that are made during the final basketball game of the season.
Mathematics
1 answer:
ale4655 [162]3 years ago
0 0

Answer:

Step-by-step explanation:

x = 2 pointers and y = 3 pointers

x + y = 32......x = 32 - y

2x + 3y = 71

2(32 - y) + 3y = 71

64 - 2y + 3y = 71

y = 71 - 64

y = 7

x + y = 32

x + 7 = 32

x = 32 - 7

x = 25

check....

2x + 3y = 71

2(25) + 3(7) = 71

50 + 21 = 71

71 = 71 (correct)..it checks out

so the solution to this system is : (25,7)

there were 25 two points shots made and 7 three point shots made

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I have corner points of:
WARRIOR [948]
The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10

So the four vertex points are:
(1,9)
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Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z

------------------

Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later. 
So let's call it A. Let A = 25

Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
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Call this value B = 21 so we can refer to it later

Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later

Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727

------------------

In summary, we found
A = 25
B = 21
C = 39
D = 22.2727

The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)

Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)

------------------

Final Answer: 39

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