Given:
Equilateral triangle: height = 2.6 inches ; base or side length = 3 inches
Rectangle: length = 6 inches ; width = 3 inches
1 name plate has 2 equilateral triangle and 3 rectangles.
Surface area of an equilateral triangle = √3/4 * a² = √3/4 * 3² = 3.9 in²
3.9 in² x 2 = 7.8 in²
Surface area of a rectangle = 6 in * 3 in = 18 in²
18 in² x 3 = 54 in²
7.8 in² + 54 in² = 61.8 in²
61.8 in² x 30 nameplates = 1,854 in² Choice A.
Let
C-------> the length of a circumference
C=2*pi*r-----> equation 1
we know that
in this problem-----> <span>the circumference of the foundation is 4 times the radius, increased by 114 ft
</span>so
C=4*r+114------> equation 2
(1)=(2)
2*pi*r=4*r+114------> 2*pi*r-4*r=114-----> r*[2*pi-4]=114---> r=114/[2*pi-4]
r=114/[2*pi-4]-----> 50 ft
the answer is
r=50 ft
Volume of a cone = 1/3 π r² h
235.5 = 1/3 (3.14) r² (9)
(3.14) r² (9) = 706.5
r² = 25
r = 5
Answer: Radius = 5 cm
Answer:
i dont know but at least add me brainliest for trying
