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3 years ago

Given f(x) = 3x - 2, find f(-6).

Mathematics

1 answer:

aliina [53]3 years ago

8 0

X=-6 so you have to plug it into x

3(-6)-2

You should get -20

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Solve the following for the specified variable Z=s/2(P+p); for P

lapo4ka [179]

Answer:

$\boxed{\sf P = \frac{2Z}{s} - p}$

Step-by-step explanation:

$\sf Solve \ for \ P: \\ \sf \implies Z = \frac{s}{2} (P + p) \\ \\ \sf Z = \frac{s}{2} (P + p) \ is \ equivalent \ to \ \frac{s}{2} (P + p) = Z: \\ \sf \implies \frac{s}{2} (P + p) = Z \\ \\ \sf Divide \ both \ sides \ by \ \frac{s}{2} : \\ \sf \implies P + p = \frac{2Z}{s} \\ \\ \sf Substrate \ p \ from \ both \ sides: \\ \sf \implies P = \frac{2Z}{s} - p$

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2 years ago

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2 years ago

Analyze the diagram below and complete the instructions that follow. Find the area of QRS.

11Alexandr11 [23.1K]

Answer-

The area of QRS is 238.7 sq units.

Solution-

According to properties of supplementary angles,

$m\angle R+124=180\\\\m\angle Q+132=180$

So,

$\Rightarrow m\angle R=180-124=56,\ m\angle Q=180-132=48$

As the sum of measurement of all the angles in a triangle is 180, so

$\Rightarrow m\angle S+m\angle R+m\angle Q=180$

$\Rightarrow m\angle S=180-m\angle R-m\angle Q$

$\Rightarrow m\angle S=180-56-48=76$

Then the area of the triangle will be,

$\text{Area}=\dfrac{1}{2}qr\sin S$

$=\dfrac{1}{2}\times 21\times 23.43\times \sin 76$

$=238.7\text{sq.units}$

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3 years ago

In the xy-plane, the point (4,4) lies on the graph of the function f(x)-2x2-bx + 12. What is the value of b?

nikdorinn [45]

Simply substitute the point into the given equation; as there is one variable, you only need one point and so one is given. When done so, you shall get b=4

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2 years ago

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Here is your answer.........

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3 years ago

Read 2 more answers