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4 years ago

Plz help me fast I really need help

Mathematics

1 answer:

Sergio [31]4 years ago

4 0

I would say that 18 is C, and I don’t know about 19

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What is the approximate value of tan C?<br><br> Please help! Urgent!

Elenna [48]

Hey there! I'm happy to help!

Tan means tangent. The tangent is the ratio of the opposite side of the angle to the adjacent side of the angle.

If we look across from angle C, we see that the opposite side is 5.

The adjacent side is the one next to the angle, and it can't be the hypotenuse (the diagonal one). Our adjacent side is 13.

So, the tangent of C is 5/13, and we can divide these, giving us about D. 0.38.

Have a wonderful day! :D

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3 years ago

What does name two integers that have the given absolute value mean

rusak2 [61]

Integers are numbers and absolute value is the magnitude of the numbe non dependent of its sign (absolute value is the number as a positive) ex; the absolute value of -3 is 3... and if the original number is positive it stays the same so ex; the abosolute value of 8 is 8

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3 years ago

Miguel has 3 times as many rabbits as Sarah. Miguel has 6 rabbits. How many rabbits does Sarah have?

ruslelena [56]

6/3=2
Sarah has 2 rabbits :)

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3 years ago

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Which is less -.72 or -7/12

Likurg_2 [28]

ok so 7 divided by 12 is 0.5833333 repeating so -0.72 is less because the bigger one is always less in the negatives

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4 years ago

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There are 255 students this term completing this same assignment. Assuming they calculated the CI correctly, how many students s

andrey2020 [161]

Answer:

The number of students we expect to have an interval that does not contain the true mean value is, $255\times [\alpha\%]$ .

Step-by-step explanation:

A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.

Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.

It is provided that 255 students create the same confidence interval, correctly.

Then the number of students we expect to have an interval that does not contain the true mean value is, $255\times [\alpha\%]$

For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:

The significance level is:

$Confidence\ level=100(1-\alpha)\\\frac{95}{100}=(1-\alpha)\\\alpha =1-0.95=0.05$

Number of students we expect to have an interval that does not contain the true mean will be: $255\times [\alpha\%]=255\times 0.05=12.75\approx13$

Thus, 13 of the 255 confidence intervals will not consist the true mean value.

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3 years ago