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kvasek [131]
3 years ago
12

Quadratic equations question 1 ^^

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

bx^2+32x=4x(x-a)\\ bx^2+32x=4x^2-4ax\\\\ b=4\\\\ -4a=32\\ a=-8\\\\ \boxed{ab=-8\cdot4=-32}

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how do you use absolute value to find the distance between two points that have the same X-coordinates but different Y-coordinat
sdas [7]
So since x coordinates are same, we just have a horizontal distance to find (no fancy slanted lines)

so what you do is
|y1-y2|=distance
6 0
3 years ago
Hey all you math geniuses can you help me with this question that should be easy
kenny6666 [7]

Answer:

(B) \frac{-3}{x}

Step-by-step explanation:

A polynomial is the expression which consists of addition, subtraction, multiplication with any variables or constants but the division with a variable is not considered as a polynomial.

Since \frac{-3}{x} consists of division of -3 with a variable, therefore it is not a polynomial, rest all other options are polynomial as they involve addition,multiplication with variables.


7 0
4 years ago
WILL GIVE BRAINLIEST!!!!
boyakko [2]

Exponential functions are known to increase geometrically. An example of exponential function is  p(x) = 500(1.02)^x

<h3>Exponential functions</h3>

Exponential functions are known to increase geometrically. The standard exponential function is given as:

y = ab^x

a is the base

x is the exponent

From the given options, the function written in this form is

p(x) = 500(1.02)^x. Hence an example of exponential function is

p(x) = 500(1.02)^x

Learn more on exponential function here: brainly.com/question/12940982

#SPJ1

8 0
2 years ago
What is the perimeter of this figure
lesantik [10]

Answer:

11+11+3+3+3= 31

Step-by-step explanatio

7 0
3 years ago
Read 2 more answers
10]The graph of a function is a line that passes through the coordinates (2, 11) and (8. 14).Which is an equation in terms of x
aksik [14]

We know that the graph of a function is a line that passes through the coordinates (2, 11) and (8, 14) and we must find the equation for the line.

1. We must use the next formula to find the slope

m=\frac{y_2-y_1}{x_2-x_1}

Where (x1, y1) and (x2, y2) are the points.

Now, replacing the points in the formula for the slope

m=\frac{14-11}{8-2}=\frac{3}{6}=\frac{1}{2}

2. We must replace the slope and one of the points in the next formula

y-y_1=m(x-x_1)

Now, replacing the slope and the point (2, 11)

\begin{gathered} y-11=\frac{1}{2}(x-2) \\  \end{gathered}

3. We must delete the parenthesis and solve the equation for y

\begin{gathered} y-11=\frac{1}{2}x-\frac{1}{2}\cdot2 \\ y-11=\frac{1}{2}x-1 \\ y=\frac{1}{2}x-1+11 \\ y=\frac{1}{2}x+10 \end{gathered}

ANSWER:

y=\frac{1}{2}x+10

8 0
1 year ago
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