Took must make a 92 on the next test.
(81+84+84+69+76+x)/6=81
(394+x)/6=81
Multiply by 6 on both sides
394 + x = 486
Subtract 394 from both sides.
x= 92
Answer:
r = 3.
Step-by-step explanation:
16 = 10 + √(3r + 27)
√(3r + 27) = 6
Square both sides:
3r + 27 = 36
3r = 36 - 27 = 9
r = 3.
Check the result:
Left side of the equation = 16
Right side = 10 + √(9 + 27)
= 10 + √36 = 16
Answer:
Step-by-step explanation:
36/24 or 3/2
The remainder of the thirty once you remove the 6 who are male.
30-6=24..
Answer:
- 891 = 3^4 · 11
- 23 = 23
- 504 = 2^3 · 3^2 · 7
- 230 = 2 · 5 · 23
Step-by-step explanation:
23 is a prime number. That fact informs the factorization of 23 and 230.
The sums of digits of the other two numbers are multiples of 9, so each is divisible by 9 = 3^2. Dividing 9 from each number puts the result in the range where your familiarity with multiplication tables comes into play.
891 = 9 · 99 = 9 · 9 · 11 = 3^4 · 11
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504 = 9 · 56 = 9 · 8 · 7 = 2^3 · 3^2 · 7
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230 = 10 · 23 = 2 · 5 · 23
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<em>Comment on divisibility rules</em>
Perhaps the easiest divisibility rule to remember is that a number is divisible by 9 if the sum of its digits is divisible by 9. That is also true for 3: if the sum of digits is divisible by 3, the number is divisible by 3. Another divisibility rule fall out from these: if an even number is divisible by 3, it is also divisible by 6. Of course any number ending in 0 or 5 is divisible by 5, and any number ending in 0 is divisible by 10.
Since 2, 3, and 5 are the first three primes, these rules can go a ways toward prime factorization if any of these primes are factors. That is, it can be helpful to remember these divisibility rules.
