Help please will mark

Mathematics

2 answers:

iren [92.7K]2 years ago

6 0

Answer:

The answer is C

Step-by-step explanation:

Wewaii [24]2 years ago

5 0

Answer:

Step-by-step explanation:

SA formula is 2lw+2lh+2hw

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I need help on how to find the slope of the first two question

nikitadnepr [17]

Remember the equation for slope is y=mx+b {m=slope, and b=y-intercept.} {Slope= rise/run}
1.) y= 2x+0
2.) y= -3/4x+0.5

P.S.: hope I helped :)

7 0

2 years ago

Read 2 more answers

Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE

AVprozaik [17]

Answer:

Step-by-step explanation:

We are given that:

$\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi$

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

$\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}$

Using double angle identities:

$\displaystyle \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}$

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

$\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}$

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence: