Answer:
f(-5) = 4(-5) + 1 = -20 + 1 = -19
f(-1) = 4(-1) + 1 = -4 + 1 = -3
f(2) = 4(2) + 1 = 8 + 1 = 9
f(3) = 4(3) + 1 = 12 + 1 = 13
f(5) = 4(5) + 1 = 20 + 1 = 21
Answer:
0.0032
Step-by-step explanation:
We need to compute 
by the help of third-degree Taylor polynomial that is expanded around at x = 0.
Given :
< e < 3
Therefore, the Taylor's Error Bound formula is given by :
, where 
Therefore, |Error| ≤ 0.0032
Answer:
dy/dx = d/dx (sin3x.cos2x)
dy/dx = cos3x . 3 . -sin2x . 2 (Using chain rule)
dy/dx = -6cos3xsin2x
That would be elimination. you could do it with substitution but i like using elimination more than substitution when theres more than 2 variables
Answer:
I believe there is an error with the problem
Step-by-step explanation:
3*6*2 + 2*6*3 + 6*2 = 36+36+12 = 84
