It allows for most equation to to visible shorter
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Answer:
Step-by-step explanation: The answer to your question is 15 pretzels.To figure this out, you first multiply 8.99 by 4 since he did buy 4 pizzas and each pizza is 8.99. Then once you do that, you should come up with 35.96. Then subtract 50.81 from 35.96,which should give you 14.85. Then just divide 14.85 by 0.99 to figure out the amount of pretzels he bought.It should give you 15.Hope this helps!!!!
Please give brainliest!!!☺
Answer:
x<-5
Step-by-step explanation:
Subtract 15 from both sides, divide both sides by 5
<h3>
Answer: Choice B</h3>
The set notation includes all values from -5 to 0, but the domain only includes the integer values
eg: something like -1.2 is in the second set, but it is not in the set {-5,-4,-3,-2,-1}
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Further explanation:
Let's go through the answer choices one by one
- A. This is false because 0 does not come before -5, but instead -5 is listed first. The order -5,-4,-3,-2,-1,0 is correct meaning that
is the correct order as well. - B. This is true. A value like x = -1.2 is in the set
since -1.2 is between -5 and 0; but -1.2 is not in the set {-5, -4, -3, -2, -1, 0}. So the distinction is that we're either considering integers only or all real numbers in this interval. To ensure that we only look at integers, the student would have to write
. The portion
means "x is in the set of integers". The Z refers to the German word Zahlen, which translates to "numbers". - C. This is false. The student used the correct inequality signs to indicate x is -5 or larger and also 0 or smaller; basically x is between -5 and 0 inclusive of both endpoints. The "or equal to" portions indicate we are keeping the endpoints and not excluding them.
- D. This is false. Writing
would not make any sense. This is because that compound inequality breaks down into
. Try to think of a number that is both smaller than -5 AND also larger than 0. It can't be done. No such number exists.
The answer is 8.45498149331, you can round it to the nearest thousandths place though, too.