Answer:
5x
Step-by-step explanation:
=> 6x-x
<u><em>Taking x common</em></u>
=> x(6-1)
=> x(5)
=> 5x
this is a question from me to you not an answer sorry what class are you taking
3x - 1 = 3x + 1
subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION
************************************************
4x - 11 = 7
add 11 to both sides and then divide both sides by 4 to get
. This statement is true only when x =
so it is: CONDITIONAL
*************************************************
2 - 8x = 2 - 8x
add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY
*************************************************
x + 1 = -x + 4
add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get
. This statement is true only when x =
so it is: CONDITIONAL
Answer: B, A, C, A
Answer:
2
Step-by-step explanation:
Plug 4 in for d and 3 in for c
5d-2/3c
5(4)-2/3(3)
Multiply in the numerator and the denominator
20-2/9
Subtract in the numerator
18/9
2
Hope this helps! :)