ANSWER
Period: 2π , amplitude: 4
EXPLANATION
The graphed function is
The amplitude of this function is
The period is 2π because there is no phase shift hence the period is still equal to the parent function.
Period: 2π , amplitude: 4
My math problem went from 10a+15=65 to 10a+15-15=65-15. Explain what happened in this step.
2 answers:
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Given:
A quadrilateral inscribed in a circle.
To find:
The values of a and b.
Solution:
A quadrilateral inscribed in a circle. So, the quadrilateral is a cyclic quadrilateral.
We know that the sum of the opposite angles of a cyclic quadrilateral is 180 degrees.
We know that the measure of arc is twice of measure of subtended angle on that arc.
Therefore, the value of a is 101 degrees and the value of b is 82 degrees.
Answer:
Step-by-step explanation:
Suppose F represents the value that a room is unlocked.
Then, we can assume that the probability of unlocked homes is:
P(unlocked homes) = P(U)
P(unlocked homes) = 40%
P(unlocked homes) = 0.40
Also, let us represent the value of the locked room with G.
P(locked homes) = P(G)
P(locked homes) = (1 - 0.40)
P(locked homes) = 0.60
Let the probability of selecting a correct key be P(S)
It implies that for the agent to use 3 keys, we have a combination of possible ways for the set of keys.
Now; since only one will open the house, then:
P(select correct key) = P(S)
P(S) = 0.375
Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:
P(F ∪ (G∩S) = P(F) + P(G∩S)
P(F ∪ (G∩S) = P(F) + P(G) × P(S)
P(F ∪ (G∩S) = 0.40 + (0.60×0.375)
P(F ∪ (G∩S) = 0.40 + 0.225
P(F ∪ (G∩S) =0.625