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Ksivusya [100]
3 years ago
8

The diagram shows rectangle ABCD on a pair of aces. The lengths of its sides are 20 units and 5 units. The coordinates of point

A are (3,9). What are the coordinates of point C?
Mathematics
1 answer:
malfutka [58]3 years ago
3 0
20...3,9
5.....x
----------
20x=5*3,9
20x=19,5
x=19,5:20
x=0,975

You can also do it like this:

20:5=4
3,9:4=0,975

I hope it's correct and it helps you. :)
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Carla runs 4 miles every day. She jogs from home to the school track, which is 3/4 mile away. She then runs laps around the 1/4
julsineya [31]
She runs 10 laps around the track I hope this helped ^^
8 0
3 years ago
In triangle XYZ right angled at Y. Find the length of the hypotenuse if the length of the other two sides is 1.6 cm and 6.3 cm.
const2013 [10]

Answer:

6.5 cm

Step-by-step explanation:

From Pythagoras theorem

C^2= a^2 + b^2

Where a, b are the sides of the triangle

C= hypotenus sides of the triangle

two sides are given as 1.6 cm and 6.3cm respectively.

C^2= 1.6^2 + 6.3^2

C^2= 2.56 + 39.69

C^2 = 42.25

C= √42.25

C=6.5 cm

Hence, the length of the hypotenuse is 6.5 cm

7 0
3 years ago
In 1924, the temperature in Fairfield, Montana, dropped from 63 degrees to -21 degrees in 12 hours. What was the average hourly
Pavlova-9 [17]
The average change hourly is 7 degrees per hour
4 0
3 years ago
Lillie and Adam are simplifying the expression 643<br><br> Whose reasoning is correct?
Luda [366]

Answer:

The first one

"Only Lillie is correct" that's the right answer.

Step-by-step explanation:

64^2/3 = 16

7 0
2 years ago
A= [2, 3; 2, 1], B=[3; 5]. Find AB &amp; BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
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