Which ordered pair represents the solution to the system of equations? {4x−2y=18−3x−4y=−8 (4, −1) (5, 1) (−1, 4) (43, 1)

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

6 0

Answer:

A g imma need the answer too

Step-by-step explanation:

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find an equation for the perpendicular bisector of the line segment whose endpoints are (-8,-5) and (-4,1)

lbvjy [14]

Answer:

y = -x - 8

Step-by-step explanation:

Midpoint of the line:

x = (x1 + x2)/2 = (-8 + -4)/2 = -12/2 = -6

y = (y1 + y2)/2 = (-5 + 1)/2 = -4/2 = -2

so midpoint is (-6,-2)

Slope of the line: Slope m = (y2-y1)/(x2-x1)

m = (-1 - -5)/(-4 - -8) = (-1 + 5)/(-4 + 8) = 4/4 = 1

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of the perpendicular line is -1/1 is -1

y = mx + b

y = -x + b

Using (-6,-2)

-2 = -(-6) + b

-2 = 6 + b

b = -8

so y = -x - 8

6 0

2 years ago

Read 2 more answers

Help plzzzzzzzzzzzzzzzzzzzzz

prohojiy [21]

Answer:

c = ${\boxed{\boldsymbol{29}}}$ km

Step-by-step explanation:

Here's the required formula to find the missing side of triangle by pythagoras theorem :

${\longrightarrow{\pmb{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}}}$

$\purple\star$ a = 20 km
$\purple\star$ b = 21 km
$\purple\star$ c = ?

Substituting all the given values in the formula to find the third side of triangle :

$\begin{gathered} \quad{\longrightarrow{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{{(20)}^{2} + {(21)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(20 \times 20) + (21 \times 21) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(400) + (441) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{400 + 441 = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{841= {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{c = \sqrt{841}}}} \\ \\ \quad{\longrightarrow{\sf{\underline{\underline{\purple{c = 29 \: km}}}}}}\end{gathered}$