Answer:
she can buy 5 movie tickets
Step-by-step explanation:
30/6=5
Answer:
492,4.93,50,493
Step-by-step explanation:
This is already in prime factored form. If you multiply 2, 3, 5, and 7 you get 2*3*5*7 = 6*35 = 210
So if your book asked "what is the prime factorization of 210?" then the answer would be 2*3*5*7
I'm using the asterisk symbol * in place of x because x is often used as a variable in algebra.
Solution:
Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.
These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:
Notice that together they make a straight angle.
Hence,
From the image
The following pairs form vertical angles
![\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle1%3D%5Cangle3%28vertical%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle2%3D%5Cangle4%28vertical%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle5%3D%5Cangle7%28vertical%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle6%3D%5Cangle6%28vertical%5Ctext%7B%20angles%29%7D%20%5Cend%7Bgathered%7D)
Hence,
One pair of the vertical angles is ∠1 and ∠3
Part B:
Two angles are said to be supplementary when they ad together to give 180°
Hence,
From the image,
The following pairs are supplementary angles
![\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle5%2B%5Cangle6%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle5%2B%5Cangle8%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle7%2B%5Cangle8%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle6%2B%5Cangle7%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle1%2B%5Cangle2%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle1%2B%5Cangle4%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle2%2B%5Cangle3%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5C%5C%20%5Cangle3%2B%5Cangle4%3D180%5E0%28supplementary%5Ctext%7B%20angles%29%7D%20%5Cend%7Bgathered%7D)
Hence,
One pair of supplementary angles is ∠5 and ∠6
2(6+w)+2(w)=40
12+2w+2w=40
12+4w=40
4w=28
w=7
Now we know that the width is 7; abd the length is 7+6 which is 13.
To find the area we multiply 13x7
The area is 92cm squared