Question

Find the accelartion:

Answer 1

A. Man runs (> 2.2 m/s is running) uphill at 6 m/s (???) and decelerates to walking at 2.0 m/s near the top, all in 5 minutes, assuming he ran in a straight line.

Acceleration is (final velocity-initial velocity (m/s) )/time (s)
=(2-6)/(5*60)=-4/300= -0.0133 m/s^2

B. Car goes east for 300 km in 45 min.
Velocity 
=300*1000 m  / (45*60) s  due east
=300000/2700 m/s due east
=111.1 m/s due east
(is it an airplane?  A cesna cruises at 63 m/s  (226 km/h) )