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devlian [24]
2 years ago
10

Find the accelartion:

Mathematics
1 answer:
bagirrra123 [75]2 years ago
6 0
A. Man runs (> 2.2 m/s is running) uphill at 6 m/s (???) and decelerates to walking at 2.0 m/s near the top, all in 5 minutes, assuming he ran in a straight line.

Acceleration is (final velocity-initial velocity (m/s) )/time (s)
=(2-6)/(5*60)=-4/300= -0.0133 m/s^2

B. Car goes east for 300 km in 45 min.
Velocity 
=300*1000 m  / (45*60) s  due east
=300000/2700 m/s due east
=111.1 m/s due east
(is it an airplane?  A cesna cruises at 63 m/s  (226 km/h) )
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If x-12y=-210and x-6y=90 then x =
Whitepunk [10]

Answer:

90

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6 0
2 years ago
Find the solutions to sin2(x) + cos(x) = 1, keeping 0 ≤ x < 2π
frozen [14]
Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
3 0
3 years ago
If the area of sector AOC is 12π cm² and the measure of the radius is 6 cm, what is the measure of the central angle in radians?
ella [17]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
If 270°<θ<360°, and tan⁡ θ= - 1/2, what is the value of tan⁡(−θ)?
stiv31 [10]

Check the picture below.

let's recall that once we move an angle in the opposite direction of the 0-line or x-axis, we end up with a negative counterpart angle.

since we know that θ is on the IV Quadrant, then its negative counterpart must be across the line, and tangent is negative on the IV Quadrant, and positive on the I Quadrant.

4 0
3 years ago
A bag contains four yellow marbles, six red marbles, five blue marbles, six white marbles, and four black marbles. What is the t
ss7ja [257]

Answer:

the answer would be D

Step-by-step explanation:

first you add all your marbles up and that is you bottom half of the equation and then you put the amount of white marbles on top.

4 0
3 years ago
Read 2 more answers
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