he solution set is
{
x
∣
x
>
1
}
.
Explanation
For each of these inequalities, there will be a set of
x
-values that make them true. For example, it's pretty clear that large values of
x
(like 1,000) work for both, and negative values (like -1,000) will not work for either.
Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are all the
x
-values that will work for at least one of them. To do this, we solve both inequalities for
x
, and then overlap the two solution set
Y=mx+b
m=slope
b=yint
find slope
slope between (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)
given
(-3,5) and (1,1)
slope=(5-1)/(-3-1)=4/-4=-1
y=-1x+b
find b
when x=1, then y=1
1=-1(1)+b
1=-1+b
add 1
2=b
y=-x+2
4 = 400/100
or 400 hundreths
Answer:
5/12
Step-by-step explanation:
First you open 2 parenthesis with x in each one:
(x )(x )=0
Then, you place the sign of the second term (the x term) in the first parenthesis.
(x+ )(x )=0
Next, you multiply the signs of the x term and the sign of the constant (the third term).
Since + × - = -, then you place a -.
(x+ )(x- )=0
You look at the constant (-18) and the second term (3). What two numbers multiplied give you -18 but subtracted (since the signs inside the parenthesis are opposite) give you 3? Those numbers are 6 and 3.
Since the result of the substraction need to be 3, you place the 6 with the + sign and the 3 with the negative sign (if you think of it, 6-3=3 but 3-6 = -3. That's the reason behind placing the numbers)
(x+6)(x-3)=0
Therefore,
x+6=0 or x-3=0
x=-6 or x=3
Your roots are -6 and 3.
