Step-by-step explanation:
We need to find an expression for 
.
We can solve it as follows.
We know that,
So,
or
Hence, this is the required solution.
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:
Step-by-step explanation:
Hope this helps!
Answer:
187/6
Step-by-step explanation:
Simplify the following:
(7 + 1/4) 2^2 + (8 + 1/2 - 2)/3
2^2 = 4:
(7 + 1/4) 4 + (8 + 1/2 - 2)/3
Put 7 + 1/4 over the common denominator 4. 7 + 1/4 = (4×7)/4 + 1/4:
(4×7)/4 + 1/4 4 + (8 + 1/2 - 2)/3
4×7 = 28:
(28/4 + 1/4) 4 + (8 + 1/2 - 2)/3
28/4 + 1/4 = (28 + 1)/4:
(28 + 1)/4×4 + (8 + 1/2 - 2)/3
28 + 1 = 29:
29/4×4 + (8 + 1/2 - 2)/3
29/4×4 = (29×4)/4:
(29×4)/4 + (8 + 1/2 - 2)/3
(29×4)/4 = 4/4×29 = 29:
29 + (8 + 1/2 - 2)/3
Put 8 + 1/2 - 2 over the common denominator 2. 8 + 1/2 - 2 = (2×8)/2 + 1/2 + (2 (-2))/2:
29 + ((2×8)/2 + 1/2 + (2 (-2))/2)/3
2×8 = 16:
29 + (16/2 + 1/2 + (2 (-2))/2)/3
2 (-2) = -4:
29 + (16/2 + 1/2 + (-4)/2)/3
16/2 + 1/2 - 4/2 = (16 + 1 - 4)/2:
29 + ((16 + 1 - 4)/2)/3
16 + 1 = 17:
29 + ((17 - 4)/2)/3
| 1 | 7
- | | 4
| 1 | 3:
29 + (13/2)/3
13/2×1/3 = 13/(2×3):
29 + 13/(2×3)
2×3 = 6:
29 + 13/6
Put 29 + 13/6 over the common denominator 6. 29 + 13/6 = (6×29)/6 + 13/6:
(6×29)/6 + 13/6
6×29 = 174:
174/6 + 13/6
174/6 + 13/6 = (174 + 13)/6:
(174 + 13)/6
| 1 | 7 | 4
+ | | 1 | 3
| 1 | 8 | 7:
Answer: 187/6
Answer:
the LCM is 6x^2(x-1)^2(x+2)
