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S_A_V [24]
3 years ago
15

IF ANYONE USES THE COMPUTER PROGRAM SCRATCH I NEED YOUR HELP!! 15 POINTS!!

Computers and Technology
2 answers:
klemol [59]3 years ago
7 0
Hello! Here are the correct answers:

Blank 1 = D) Reports true if the mouse button is pressed.

Blank 2 = D) Reports the x coordinate position of the mouse.

Blank 3 = C) Vertical Position of the mouse.

I hope you found my answers helpful! :)
Irina-Kira [14]3 years ago
4 0
The mouse down block C, 2) is c, and
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On a client/server network, data does not necessarily follow the same path between the request (client) and the response (server
Andrej [43]

Answer:

SSL and HTTPS play a factor

6 0
2 years ago
Selah infects the ads on a website that users from her target company frequently visit with malware as part of her penetration t
ValentinkaMS [17]

Selah infects the ads on a website with a technique called the Watering hole attacks.

<h3> What is Watering hole attacks?</h3>

The  Watering hole attacks is known to be a form of attack that depends on compromising or infecting a website that has or that targeted users who are known to often frequently visit.

So, Selah infects the ads on a website with a technique called the Watering hole attacks.

Learn more about malware from

brainly.com/question/399317

#SPJ1

8 0
1 year ago
The customer's endpoint device on the wan is called the __________________.​
Lelu [443]
<span>The customer's endpoint device on the WAN is called the Data Terminal Equipment (DTA).
WAN 
is wide area network, referring to a network that extends over a large area. DTA is an end instrument which converts information into signals.</span>
3 0
3 years ago
If a 60 lb. load is placed on the platform, what will the pressure gauge reading be if the piston area is 5 sq.in? Give your ans
Doss [256]

Answer:

The pressure gauge reading will be;

12 psi

Explanation:

The question relates to relationship of pressure and area

The given parameters for the measurement are;

The weight of the load = 60 lb

The required area of the piston = 5 in.²

Pressure exerted by a force can be defined as follows;

Pressure =  \dfrac{Force}{Area}

The weight of the load = The force applied by the load

Therefore;

Pressure =  \dfrac{Force}{Area} = \dfrac{60 \ lb}{5 \ in.^2}  = 12\dfrac{lb}{in.^2} = 12 \ psi

The gauge reading will be 12 psi.

7 0
3 years ago
Read 2 more answers
There are two String variables, s1 and s2, that have already been declared and initialized. Write some code that exchanges their
Ivan

Answer:

//here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare an initialize first string variables

     String st1="hello";

     // declare an initialize first string variables

     String st2="world";

     // create another string variable

    String st3;

    // exchange the value of both string variables

    st3=st1;

    st1=st2;

    st2=st3;

    System.out.println("value of first String after exchange: "+st1);

    System.out.println("value of second String after exchange: "+st2);

   }catch(Exception ex){

       return;}

}

}

Explanation:

declare and initialize two string variables.Create another string variable "st3". first assign value of "st1" to "st3" after then value of "st2" to "st1" and then  assign value of "st3" to "st2". This will exchange the values of both the string.

Output:

value of first String after exchange: world

value of second String after exchange: hello

8 0
3 years ago
Read 2 more answers
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