Answer:
I've implemented this program using python
userinput = int(input("Length: "))
mylist = []
mylist.append(userinput)
for i in range(1,userinput+1):
userinp = int(input("Input: "))
mylist.append(userinp)
smallval = mylist[1]
for i in range(1,len(mylist)):
if smallval > mylist[i]:
smallval = mylist[i]
for i in range(1,len(mylist)):
mylist[i] = mylist[i] - smallval
for i in range(1,len(mylist)):
print(mylist[i],end=' ')
Explanation:
I've added the full source program as an attachment where I used comments to explain difficult lines
Joystick..................:-)
"A Buffer overflow" vulnerability exploit resulted from the attacker's actions.
Whenever a software or an application writes too much data into a buffer, causing neighboring storage regions to have been corrupted as a consequence, this could be determined as Buffer overflow.
⇒ There are two kinds of Buffer overflow attacks such as:
- <u>Stack-based</u> - It will become more popular to use such memory, as well as that's only available during implementation of any code.
- <u>Heap-based</u> - Those attacks seem to be more difficult to execute because they entail overflowing overall storage capacity allotted for a program further than the space needed for something like the program's present activities.
Thus we can say that the correct answer is a Buffer overflow.
Learn more about Buffer overflow here:
brainly.com/question/4952591
Answer:
A. Rogue access point
Explanation:
A rogue access point is defined as a wireless access point installed on a secure network infrastructure without consent of the owner of the network or without due authorization. While this can sometimes be added by a malicious attacker, it is most commonly set up by employees with the desire to have wireless access even when there is any available.
In the question, there are three wireless networks, but on scanning, five wireless networks were found, hence they are rogue access point.
Answer:A flowchart is a diagram that depicts the steps involved in solving a problem. The following flowchart shows how to output the multiplication table ( n * 1 to m * 1) of a number, n and m:
