Answer:
The answers are "Option a, Option b, Option d, and Option c".
Explanation:
- The Traceroute utilizes the "Internet Control Message Protocol" for transmit and receive echo-request and echo-reply messages. This is most often used in the echo packets of specified interval to live (TTL) quantities.
- The Transport layer will be the next but is usually directly linked with the same name layer in the OSI model. Functions involve message fragmentation, acknowledgment, traffic management, session parallelization, error detection, as well as message rearranging.
- Leaders generally fully involve one or even more workers in design buildings.
- 67 was its UDP port number which is used as the port number of a database. So although UDP port number 68 is being used by the client.
Answer: Socio-technical systems
Explanation:
Sociotechnical systems refers to an approach to organizational work design whereby the interaction between people and technology in the workplace is recognized.
It should be noted that the welfare of the worker is emphasized in socio technical systems is emphasized in the form of motivation and job enrichment.
steve is happy today but he wasn't yesterday
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
