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labwork [276]
3 years ago
11

della bought a tree seedling that was 2 1/4 feet tall. during the first year, it grew 1 1/6 feet. after 2 years it was 5 feet ta

ll. how much did the seedling grow during the 2nd year?
Mathematics
2 answers:
koban [17]3 years ago
5 0
If you would like to know how much did the seedling grow during the 2nd year, you can calculate this using the following steps:

during the first year: 2 1/4 feet + 1 1/6 feet = 9/4 + 7/6 = 27/12 + 14/12 = 41/12 = 3 5/12 feet

after two years: 5 feet - 3 5/12 feet = 5 - 41/12 = 60/12 - 41/12 = 19/12 = 1 7/12 feet

The seedling grew 1 7/12 feet during the 2nd year.
alexira [117]3 years ago
5 0
2 \frac{1}{4} + 1 \frac{1}{6} = 3 \frac{5}{12}-5=1 \frac{7}{12}
1 \frac{7}{12} is the answer
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Martha drew a pair of intersecting non-perpendicular lines, I and m. She numbered one pair of vertical angles <1 and <2, a
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3 years ago
What is the remainder when 3x2 - X - 10 is divided by x - 1? T
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3 years ago
7 times as much as sum of 1/3 and 4/5
Salsk061 [2.6K]
So the formula is
7*(1/3+1/5) = x

First find the common denominator of the fractions.  In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths.  To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.

So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it

5 * 1 = 5 so 1/3 converts to 5/15

Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it

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7*17/15

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We have 119/15 which when we divide and get 7 14/15 as your answer
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3 years ago
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