Answer:
Step-by-step explanation:
To find the slope of the tangent at a point we will find the derivative of equation at that point.
a). y = x² - 10x 

y' = 2x - 10
At (x = 2),
y' = 2(2) - 10
y' = 4 - 10
y' = -6
From the given equation,
y = 2² - 10
y = -6
Therefore, y-coordinate of the point is y = -6
Equation of the tangent at (2, -6) having slope = -6
y - 2 = -6(x - 2)  
y - 2 = -6x + 12
y = -6x + 14
b). y = 
At x = 
y = 
y = 
y = 
Now we have to find the equation of a tangent at 
y' = 2x - 
At x = 
y' = 
y' = 1 - 8
y' = -7
Therefore, equation of the tangent at  will be,
 will be,

y = -7x + 
y = -7x + 
 
        
             
        
        
        
X midpoint: 0.5
Y midpoint: -0.5
        
                    
             
        
        
        
Answer:
40 · sqrt(pi)/pi I believe
Step-by-step explanation:
 
        
             
        
        
        
Maybe Option 2? Not really sure just trying to help
        
             
        
        
        
V ≈ 15.63cm^3
volume of a cube = side × side × side = units^3
Volume = 2.5*2.5*2.5 = 15.63^3
<em>Hoped this helped!</em>