Question

Three forces of sizes 15n,7n and 19n pulling at 120 degrees to each other are acting on a particle. What is the size of the resultant force and the direction

Answer 1

Answer:

10.58 N

Step-by-step explanation:

Let us find component of these forces in x and y direction.

The solution along with diagram can be found in attachment.

We have found resultant in X- direction = 6√3 N

resultant in Y- direction = 2 N

therefore net force resultant force = $\sqrt{(6\sqrt3)^2+2^2}$

= 10.58 N