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2 years ago

M<10 = x; m<11 = x + 20; x =

Mathematics

1 answer:

N76 [4]2 years ago

7 0

Answer:

Step-by-step explanation:

nice more free coins that is nice

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The original price of a scarf was $16. During a store closing sale, a shopper saved $12 on the scarf. What percentage discount d

Andreyy89

Answer:

The discount which she received is 25 %

Step-by-step explanation:

Given as :

The original price of scarf = $ 16

The selling price of scarf = $ 12

Let The discount percentage = d %

So,

Discount percentage = $\frac{\textrm market price-\textrm selling price}{\textrm market price}$ × 100

or, d % = $\frac{16-12}{16}$ × 100

Or, d % = $\frac{400}{16}$

∴ d = 25%

Hence The discount which she received is 25 % Answer

6 0

3 years ago

Simplify the expression. 5 + 4 • (8 – 6)2

aliya0001 [1]

5 + 4 • (8 - 6)2 = 5 + 4 • (2)2 = 5 + 4 • 4 = 5 + 16 = 21

8 0

3 years ago

What other information do you need to prove INF=CAT by the ASA postulate

Simora [160]

D. NI = AC is the needed information to prove ΔINF = ΔCAT by the ASA Postulate.

For the triangles to be congruent by ASA, the measurements of two angles and one side must be proven congruent. Since two sets of congruent angles are already given, one side must also be congruent.
When proving congruency using ASA, the congruent parts of the triangles must be in this order: Angle, Side, Angle. So, you have to the side that is between the two sets of congruent angles.

4 0

3 years ago

Read 2 more answers

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Prove that root 2 itrational number

Zolol [24]

Answer:

can you explain yourself more please

4 0

3 years ago