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2 years ago

M<10 = x; m<11 = x + 20; x =

Mathematics

1 answer:

N76 [4]2 years ago

7 0

Answer:

Step-by-step explanation:

nice more free coins that is nice

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A bag contains purple marbles and white marbles, 95 in total. The number of purple marbles is 1 less than 5 times the number of

Soloha48 [4]

Answer:

Step-by-step explanation:

95 divided by 5 equals 19

19-1=18

4 0

3 years ago

7n+12=1/2(14n+24)<br><br><br> NEED ANSWER ASAP

Angelina_Jolie [31]

Answer:

n = all real numbers

Step-by-step explanation:

7n+12=1/2(14n+24)

multiply each side by 2

2(7n+12)=2*1/2(14n+24)

distribute

14n+24 = 14n + 24

subtract 14n from each side

14n-14n+24 = 14n-14n + 24

24=24

this is always true

n = all real numbers

3 0

3 years ago

Reflect the point (2, -4) over the y-axis.

diamong [38]

Answer:

I think its a. (-2,-4)

Step-by-step explanation:

7 0

3 years ago

tenesa bought a 50 pound bag of flour for her bakery. she used 13.65 pounds of flour. how many pounds of flour are left in the b

saw5 [17]

Answer: 36.35

work:
50 - 13.65 = 36.35

4 0

3 years ago

Read 2 more answers

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago