Dividir 85 en dos partes tales q el triple de la parte menor equivalente al doble de la mayor

The table below shows the relative frequencies of the color of cars bought last month by males and females. Which percentage rep

bezimeni [28]

31%.

The car bought most often by both males and females collectively is the white car. That has a total frequency of 0.31 out of 1 or, 31/100

3 0

3 years ago

В. Solve what is asked. Show your solutions on your answer sheet. Label your final answers

zimovet [89]

9) We have: 23,15% × 35 = 8,1025 kg

There are 8,1025 kilograms of cashew nuts were there in the mixed nuts

10) We have:

25 × 64% = 16 mangoes
25× 16% = 4 avocados

8 0

3 years ago

The state highway patrol wants to evaluate a new rule for vehicles that was put into place to prevent road accidents across all

Mnenie [13.5K]

Jcjcjcjcjcjcjcjcjcjcj

3 0

3 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

1 year ago

How many child tickets were sold that day?

ExtremeBDS [4]

$\huge\boxed{\fcolorbox{black}{red}{Answer}}$

first let's name a couples of variable

• the number of adults tickets sold: a

• the number of children tickets sold: c

From the problem we know

a + c = 128

and

$5.40c + $9.20a = $976.20

1) solve the equation to alpha

a+c-c = 128 -c

a+0=128-c

a=128-c

2) substitute (128 - c) for a in the second equation and solve to c

$5.40c + $9.20a = $976.20 become

$5.40c + $9.20(128 - c) = $976.20

$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20

$5.40c - $9.20c + $ 1177.6 = $976.20

($5.40 - $9.20)c +$1177.6 = $976.20

-$3.80c + $1177.6 = $9.76.20

-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60

-$8.30c + 0 = $201.40

-$3.80c = - $201.40

-$3.80c. -$201.40

________. = _________

-$3.80. -$3.80

-$3.80c. -$201.40

________. = _________. - they are 4 cut the no

-$3.80. -$3.80

c = $201.40

________

3.80

c = 53

3 0

2 years ago