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Goshia [24]
3 years ago
10

PLEASE HELP! WILL MARK BRAINLIEST! Name the algebraic property demonstrated in the example below:

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0
Not a comic section
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108 - 271 + 215-_____= -103
kupik [55]
108-271+215-_____=-103
Im going to combine the first thee numbers and replace the blank with a variable, lets use x. 
52 - x=-103
now I am going to subtract 52 on both sides to get the variable alone
-x=-155
Im going to multiply both sides to eliminate the negitive in the variable
x=155
If you want to check just plug 155 into the blank
108-271+215-155=-103
-163+215-155=-103
52-155=-103
-103=-103

so after checking work the blank is equal to 155.


5 0
4 years ago
Between which two integers does √ 45 lie? 44 and 46 22 and 23 6 and 7 7 and 8
erastovalidia [21]

Answer:

6 and 7

Step-by-step explanation:

lol just use a calculator ツ

5 0
3 years ago
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

5 0
3 years ago
20. Jane and Richard each painted about 1/5
Tatiana [17]

Answer:

I can't draw a picture but its possible cuz they painted ABOUT 1/5 of the bird house so Jane could have painted a bit more than 1/5 but it would still be about 1/5

3 0
3 years ago
How many arangments of letters in PARALLEL
coldgirl [10]
There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360
5 0
3 years ago
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