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MrRa [10]
2 years ago
5

Find the value of the power

Mathematics
2 answers:
bazaltina [42]2 years ago
7 0
1
1 to any power is 1.
dedylja [7]2 years ago
3 0

Answer:

5

Step-by-step explanation:

cus the power

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cow is 65bpm

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Step-by-step explanation:

cow is given

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Pooopie ok or no ok?
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Step-by-step explanation:

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An equation that involves a multiplication addition, contains a variable, and has a solution of 8.
yulyashka [42]
A variable is an unknown like x so 

first we start with 
x=8
then we subtract (because you must add to reverse subtraction)
x-2=8-2
x-2=6
then we divide ( because you must multiply to reverse division)
(x-2)/3=6/3
(x-2)/3=2

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7 0
3 years ago
The function f(x)=x^2 -6x+3 is transformed such that g(x)=f(x-2). Find the vertex of g(x).
Lisa [10]

Answer:

g(x) = (x-2)^2 -6(x-2) +3

g(x) = x^2 -4x +4 -6x +12 +3

g(x) = x^2 -10 x +19

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

Step-by-step explanation:

We have this original function given :

f(x) = x^2 -6x +3

And we want to find the vertex for this new function g(x) = f(x-2) and we have:

g(x) = (x-2)^2 -6(x-2) +3

And solving the square we got:

g(x) = x^2 -4x +4 -6x +12 +3

And adding similar terms we got:

g(x) = x^2 -10 x +19

Now we can complete the square like this:

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

The general equation is given by:

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

5 0
4 years ago
the sum of three numbers is 61. the second number is 6 times the first. and the third number is 5 more than the second. find the
mr_godi [17]
x-the\ first\ number\\6x-the\ second\ number\\6x+5-the\ third\ number\\\\(x)+(6x)+(6x+5)=61\\x+6x+6x+5=61\\13x+5=61\ \ \ \ |subtract\ 5\ from\ both\ sides\\13x=56\ \ \ \ |divide\ both\ sides\ by\ 13\\\boxed{x=\frac{56}{13}\to x=4\frac{4}{13}-the\ first\ number}\\\boxed{6x=6\cdot\frac{56}{13}=\frac{336}{13}=25\frac{11}{13}-the\ second\ number}\\\boxed{6x+5=25\frac{11}{13}+5=30\frac{11}{13}-the\ third\ number}
6 0
3 years ago
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