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Ostrovityanka [42]
3 years ago
6

You and two friends rent a hotel room that costs $30 so you both put in $10 each later that night the owner of the hotel realize

s he has overcharged you so he sends the bellhop with $5 the bellhop steals $2 and returns $1 to each of you you each paid $9.$9 times $3 =$27 the bellhop has stole $2 that equals $29 what happened to the last dollar
Mathematics
2 answers:
Misha Larkins [42]3 years ago
6 0
They paid $30, but the owner returned $5, which means the cost is only $25. The bellhop knows this, so he take $2 of the $5 leaving $1 to be return to each person. That means that they each paid $9 making it a total of $27, more than the cost of the room. You don't need to add $2 to the $27, because that wasn't the cost of the room. The cost was only $25, so +$5 =30. So no money is actually missing, they just added incorrectly.
Gennadij [26K]3 years ago
4 0
The dollar didn't go anywhere! The question isn't correct because the money the bellhop stole is supposed to be subtracted, not added. So if we subtract $2 we have $25, and that's how much money the owner got, the men got $3 back and the bellboy got $2.

So the owner gets $25, the men get $3 and the bellboy gets $2, and that equals 30.
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25° 35° to 205° circle ​
Lisa [10]

Answer:

x = 60

Step-by-step explanation:

the chord- chord angle x is half the sum of the measures of the arcs intercepted by the angle and its vertical angle.

The sum of the arcs in a circle = 360° , then

intercepted arc = 360° - (35 + 25 + 205)° = 360° - 265° = 95°

then

x = \frac{1}{2} (95 + 25 ) = \frac{1}{2} × 120 = 60

3 0
2 years ago
Hey can you please help me posted picture of question
mote1985 [20]
Two events are occurring:

1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3

Probability of getting an odd number = 3/6 

2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2

The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12 

Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario. 

So correct answer is option C

4 0
3 years ago
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Michael bought 0.44 pound of slice turkey. what is the value of the digit in the hundredths place?
jarptica [38.1K]

Answer:

4

Step-by-step explanation:

You have 0.44

0 is in the ones place

4 is in the tenths place (0.4)

And the other 4 is in the hundredths place (0.04)

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Preston and horation have 49 video games total. Horation has 11 more than preston. How many games does each person have?
Makovka662 [10]
Preston has 19 games and Horation has 30.
4 0
3 years ago
2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
11Alexandr11 [23.1K]
There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
\frac{1}{n} = \frac{1}{a} + \frac{1}{b}

\frac{1}{n} = \frac{a + b}{ab}
and thus, n = \frac{ab}{a + b}

<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = \sqrt[a]{c} = c^{\frac{1}{a}}

Then, 5 = c^{\frac{1}{b}}
and 10 = c^{\frac{1}{n}}

But, 10 = 5·2, so 10 = c^{\frac{1}{b}}·c^{\frac{1}{a}}
∴ c^{\frac{1}{n}} = c^{\frac{1}{b}}·c^{\frac{1}{a}}

\frac{1}{n} = \frac{1}{a} + \frac{1}{b}
and n = \frac{ab}{a + b}
4 0
3 years ago
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