Answer:
1) Categorical
2) Norminal
Step-by-step explanation:
1)
The data collected by Kroger in this example categorical or quantitative identified below:
From the given information, Kroger uses an online customer opinion to obtain the data about its products and services. All the questions based on yes or no type questions. Here the questions are ‘products that have a brand name, products that are environmentally friendly, products that are organic’ these type of questions cannot be expressed numerically so the data collected by Kroger Company is categorical variable because these answers of the questions cannot be counted.
Any variable which is grouped into two or more attributes then it is a categorical variable. The data collected by Kroger Company is categorical variable and any variable which can be counted or measured in numerical then it is quantitative variable.
2)
The measurement scale is identified below:
Here the variable cannot be counted in numerical sale so the level of measurement cannot be ratio, interval because ratio and interval scale can be used for numerical data. The nominal scale can be used to identify the ‘products that have a brand name, products that are environmentally friendly, products that are organic, products that have been recommended by others’ because natural order need not be used.
The ratio and interval scale can be used for Quantitative data and nominal and ordinal scale can be used for Qualitative data. When the order is needed to categorize the objects Ordinal scale is used, when the order is not needed to categorize the objects Nominal scale is used.
Answer:
Total = 2,400 * (1 + (.083/4))^4*5
Total = 2,400 * (1.02075)^20
Total = 2,400 * 1.5079528829
Total = 3,619.09
Step-by-step explanation:
Answer:
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
-1. 34
0.1837
Step-by-step explanation:
Full time :
n1 = 125
x1 = 2.7386
s1 = 0.65342
Part time :
n2 = 88
x2 = 2.8439
s2 = 0.49241
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
Test statistic :
The test statistic :
(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]
(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]
−0.1053 / sqrt(0.0034156615712 + 0.0027553)
-0.1053 /0.0785554
= - 1.34
Test statistic = - 1.34
The Pvalue :
Using df = smaller n - 1 = 88 - 1 = 87
Pvalue from test statistic score ;
Pvalue = 0.1837
Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.
At α = 0.01 ; the result is insignificant
Answer: 
Step-by-step explanation:
A direct variation equation has the form:
Where <em>k</em> is a constant.
By definition, we know that the perimeter of the square is the sum of the lengths of its sides or, as all the sides are equal, you can multiply the lenght of any side by 4.
Then, knowing that <em>y</em> is the dependent value and <em>x</em> the independent value and the constant <em>k=4, </em> you can write the following direct variation equation that represents the situation.
Answer:
- <u><em>Option D. 0.50</em></u>
Explanation:
1. Two-way table:
Calories per Day:
1000 to 1500 1500 to 2000 2000 to 2500 Total
Weight
120 lb. 90 80 10 180
145 lb. 35 143 25 203
165 lb. 15 27 75 117
Total 140 250 110 500
2. Total number of persons
Look at the intersection of the totals for the columns and the rows: 500
3. Number of persons that consume 1,500 to 2,000 calories in a day
Look at the total for the column 1,500 to 2,000 calories per day: 250
4. Probability that a person consumes 1,500 to 2,000 calories in a day, P
- P = number of persons that consume 1,500 to 2,000 calories / total number of persons
- P = 250 / 500 = 0.50 ↔ option D.
