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Elan Coil [88]
3 years ago
8

Marylou is blowing up a beach ball. The package says that the ball has a diameter of 18 inches. What is the volume of the beach

ball when it is completely full?

Mathematics
2 answers:
Arturiano [62]3 years ago
7 0
<span>Use the formula below to find the volume of the beach ball.
Remember that the radius is one-half of the diameter.
 V=3/4 pi r^3 =4/3(3.14)(9 in)^3 =3,052.08
Therefore, the beach ball has a volume of 3,052.08 cubic inches when it is completely full.


</span>

IRINA_888 [86]3 years ago
7 0

Answer:

ithe

Step-by-step explanation:

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54. The triangles in the diagram below are congruent.
Reika [66]

Answer:

Angle N should be 64

Step-by-step explanation:

A triangle adds up to 180. So triangle JKL already has 60 towards 180. Triangle ONM already has 56 towards 180. So you have to find the other value needed in order to make 180. 56+60= 116 so we need to find the other angle to make 180. To do so just subtract 180-116 and that gives tou the answer 64 so that would be Angle N

7 0
3 years ago
For each pair of corresponding vertices, find the ratio of x-coordinates
Mumz [18]

Answer:

Hmmm

Step-by-step explanation:

5 0
3 years ago
Use the substitution method to solve the system of equation.choose the correct ordered pair. 2
Jlenok [28]
I’m not sure if the 2 is counted in the equation or not

Since x=4, substitute it for x in the other equation

4+3y=29
3y=25
Y=8.333333333

2(4)+3y=29
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y=12.33333333
7 0
3 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
Write in simple radical form:
WARRIOR [948]

Answer:

The answer to your question is \frac{2}{3}

Step-by-step explanation:

Here, there is a difference of squares, so just solve it and simplify

              ( 1 + \frac{1}{\sqrt{3} } ) (1 - \frac{1}{\sqrt{3} } )

Multiply the binomials

             = 1 - \frac{1}{3}

Simplify

             = \frac{3 - 1}{3}

             = \frac{2}{3}

7 0
3 years ago
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