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NISA [10]
3 years ago
10

Helppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

The expression x²-14x+31=63 is a quadratic equation. To solve it, you must order it:


 x²-14x+31-63=0

 x²-14x-32=0


 Then, you must apply the quadratic formula, which is shown below:


 x=(-b±√(b^2-4ac))/2a


 So you have the values of a,b and c:

:

 a=1

 b=-14

 c=-32


 When you substitute those values in the quadratic formula, you obtain:


 x=(-(-14)±√((-14)^2-4(1)(-32))/2(1)

 x1=-2

 x2=16

 So, the correct option is the third one: x=-2 or x=16

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\boxed{ \huge\boxed{ \mathcal{A}\mathfrak {nswer...}}}

The equation of a circle is represented as :

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