Answer:
A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 18, 22. Column 2 is labeled y with entries 2, 3, 4.
Step-by-step explanation:
cv
-1 Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20
+
5
=
25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25
−
6
=
19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19
−
20
=
−
1
and this makes sense because we know we advanced 5 and fell back 6
Answer:
(r o g)(2) = 4
(q o r)(2) = 14
Step-by-step explanation:
Given
Solving (a): (r o q)(2)
In function:
(r o g)(x) = r(g(x))
So, first we calculate g(2)
Next, we calculate r(g(2))
Substitute 9 for g(2)in r(g(2))
r(q(2)) = r(9)
This gives:
{
Hence:
(r o g)(2) = 4
Solving (b): (q o r)(2)
So, first we calculate r(2)
Next, we calculate g(r(2))
Substitute 3 for r(2)in g(r(2))
g(r(2)) = g(3)
Hence:
(q o r)(2) = 14
<h2>
Answer:</h2>
<h2>Step-by-step explanation:</h2>
<h2>Given :</h2>
<h2>To Find :</h2>
<h2>Solution :</h2>
We have to add 1 in numerator and -10 in denominator because
![\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cfrac%7B8%7D%7B101%7D%20%2C%20%5Cfrac%7B9%7D%7B91%7D%20%2C%20%5Cfrac%7B10%7D%7B81%7D%20%2C%20%5Cfrac%7B11%7D%7B71%7D%20...%5BGiven%5D)
The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.
Width: x
Length: 2x
Perimeter=2x+2x+x+x=6x
32 cm more than width means x+32
6x=x+32
5x=32
x=6.4
Dimension is 6.4×12.8 (width×length)
