Answer:
The volume of the cone is 100.48 units³ approximately
Step-by-step explanation:
To find the volume of a cone with a diameter of 8 unit and height of 6 units, we will follow the steps below;
first, write down the formula for calculating the volume of a cone
v= πr²
where v is the volume of the cone
r is the radius and h is the height of the cone
from the question given, diameter d = 8 units but d=2r which implies r=d/2
r=8/2 = 4 units
Hence r= 4 units
height = 6 units
π is a constant and is ≈ 3.14
we can now proceed to insert the values into the formula
v= πr²
v ≈ 3.14 × 4² × 6/3
v ≈ 3.14 × 16 × 2
v ≈ 100 .48 units³
Therefore the volume of the cone is 100 .48 units³ approximately
Answer:
PG ≅ SG (Given)
PT ≅ ST (Given)
GT = GT (Common)
∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom)
Step-by-step explanation:
<u>Given</u>: PG ≅ SG and PT ≅ ST
<u>To Prove</u>: ∠GPT ≅ ∠GST
<u>Proof</u>: PG ≅ SG (Given)
PT ≅ ST (Given)
GT = GT (Common)
∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom).
<u>SSS Congruency Axiom</u>: If three pairs of sides of two triangles are equal in length, then the triangles are congruent.
<u>Congruence</u>: Two sets of points are called congruent if, and only if, one can be transformed into the other by an isometry, i.e., a combination of rigid motions, namely a translation, a rotation, and a reflection. This means that either object can be repositioned and reflected (but not resized) so as to coincide precisely with the other object. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.
Answer:
Step-by-step explanation:
<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...
To find 
, identify the perfect squares immediately <u>before</u> and <u>after</u> 75:
See the attachment for the correct placement of on the number line.
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
