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3 years ago

Simplify: -3(y + 2)^2– 5 + 6y What is the simplified product in standard form?

Mathematics

2 answers:

Ymorist [56]3 years ago

7 0

-3(y²+4y+4) - 5 +6y

-3y² - 12y - 12 -5 + 6y

-3y² -6y -17

-(3y²+6y+17)

VMariaS [17]3 years ago

4 0

Answer:

-3y^2 - 6y - 17

Step-by-step explanation:

-3(y + 2)^2 - 5 + 6y =

Expand the square of the binomial.

= -3(y + 2)(y + 2) - 5 + 6y

Use FOIL to multiply the binomials.

= -3(y^2 + 2y + 2y + 4) - 5 + 6y

Combine like terms inside the parentheses.

= -3(y^2 + 4y + 4) - 5 + 6y

Distribute the -3.

= -3y^2 - 12y - 12 - 5 + 6y

Combine like terms.

= -3y^2 - 6y - 17

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mrs_skeptik [129]

Answer:

You could use a measurement of 4 centimeters.

The valid range is 2 < x < 8 cms.

Step-by-step explanation:

The third side must either be less than 3+5, that is less than 8 cms and it must be greater than (5-3) = 2 cms. If it is any other length we could not construct a triangle.

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3 years ago

What is the slope of the line passing through (1, 2) and (3, 3)?

enot [183]

Answer:

Slope is 1/2

Step-by-step explanation:

Using the slope formula y₂-y₁/x₂-x₁

(x₁,y₁) and (x₂,y₂) → (1,2) and (3,3)

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3 years ago

Find (r-s) (t-s) + (s-r) (s-t) for all numbers r, s, and t. (a) 0 (b) 2 (c) 2rt (d) 2(s-r) (t-s) (e) 2(r-s) (t-s)

lyudmila [28]

Notice that the 2 expressions have 2 common terms.

(r-s) is just (s-r) times (-1)

similarly

(t-s) is just (s-t) times (-1)

this means that :

(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)

the 2 minuses in the first multiplication cancel each other so we have:

-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)

Answer:

d)<span>2(s-r) (t-s) </span>

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3 years ago

Read 2 more answers

1. Two or more linear inequalities in the same variable x and y are called

Serjik [45]

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3 years ago

Please help me on this it’s due

olya-2409 [2.1K]

<h3>Answer: 5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\$

Do the same for the other mixed number 2 & 1/3.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\$

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From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

$\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\$

The last step is to convert that result to a mixed number.

$\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\$

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

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Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

3 0

3 years ago