Given:
μ = 2 min, population mean
σ = 0.5 min, population standard deviation
We want to find P(x>3).
Calculate the z-score
z= (x-μ)/σ = (3-2)/0.5 = 2
From standard tables, obtain
P(x ≤ 3) = P(z ≤ 2) = 0.9772
Therefore
P(x > 3) = P(z > 2) = 1 - 0.9772 = 0.0228
Answer: 0.02275
Answer:
Step-by-step explanation:
Here, we add up two polynomials shown.
The polynomials are:
![[-m^2 + 6]+[-4m^2 +7m + 2]](https://tex.z-dn.net/?f=%5B-m%5E2%20%2B%206%5D%2B%5B-4m%5E2%20%2B7m%20%2B%202%5D)
In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.
We add up the "
" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\
![[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8](https://tex.z-dn.net/?f=%5B-m%5E2%20%2B%206%5D%2B%5B-4m%5E2%20%2B7m%20%2B%202%5D%5C%5C%3D-m%5E2-4m%5E2%2B6%2B2%2B7m%5C%5C%3D-5m%5E2%2B7m%2B8)
This is the sum of the 2 polynomials shown:
<span>1. </span>The probability that one of the diners orders fish = number of diners who ordered fish / total number of diners
p1=45/100=0.45
<span>2. </span>The probability that one of the diners is wearing dress= number of diners wearing dress/ total number of diners
<span>3. </span>p2=14/100=0.14
<span>The probability that one of the diners ordered the fish or is wearing a dress is: p=0.45+0.14=0.59</span>
The probability of you being the leadoff hitter is <span>8.3%.</span>
Explanation:
The number of possible rosters can be calculated with permutations, knowing that the coach can choose the first hitter among all 12 players, then the second hitter among the 11 players remaining and so on until the 9th hitter among the remaining 4 players.
Therefore:
Possible rosters = 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 79833600
The leadoff hitter is the first player in the batting order, therefore the number of possible rosters in which you are chosen as the first one is:
You leadoff = 1 <span>× 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 6652800
The probability of you being leadoff is:
P</span> = You leadoff / <span>Possible rosters
</span> = 6652800 / 79833600
= 1 / 12
= 0.08333
= 8.3%
Note that this is exactly the probability of you being chosen out of the 12 players of the team in a one-pick choice because it does not matter how the rest of the batting order is composed.
